如何在oracle SQL开发人员中插入数据

问题描述 投票:0回答:1

我想在Oracle SQL Developer中插入数据。在客户端(我的意思是网页)上,它显示数据已插入,但是当我在SQL Developer中检查它时,没有插入任何数据。

而且我看到此错误消息:

由以下原因引起:错误:1400,位置:88,Sql =插入到记事本(NUM,NAME,EMAIL,CONTENTS)值(BOOK_NUM.NEXTVAL,:1,:2,:3),OriginalSql =插入到记事本(NUM ,名称,电子邮件,内容)值(BOOK_NUM.NEXTVAL,?,?,?),错误消息= ORA-01400:NULL(“ C ## YESMONDAY”。“ NOTICEBOOK”。“ CONTENTS”)

似乎查询不正确,但是我找不到错误的地方。

查看页面(main.jsp)

<body>
<h1>Notice Board</h1>
<div id="wrap">
    <div id="wrap_form">
        <form action="mainWritePro.jsp" method="post">
            <table>
                <tr>
                    <td></td>
                    <td><input type="text" name="name" placeholder="TITLE "></td>
                </tr>
                <tr>
                    <td></td>
                    <td><input type="text" name="email" placeholder="EMAIL "></td>
                </tr>
                <tr>
                    <td> </td>
                    <td>
                        <textarea rows="15" cols="50" placeholder="INQUIRY"></textarea>
                    </td>
                </tr>
                <tr class="send">
                    <td colspan="2" align="center"><input type="submit" name="" value="SEND" ></td>
                </tr>
            </table>
        </form>
    </div>
    <ul>
        <li><a href="#">DELETE</a></li>
        <li><a href="#">UPDATE</a></li>
        <li><a href="#">LIST</a></li>
    </ul>
</div>

noticeBoardVO.java

package edu.kosta.vistorsPrac;

public class noticeBoardVO { // Model
    private int num; private String name, email, contents;
    public noticeBoardVO() {} 

    public int getNum() {   return num; }
    public void setNum(int num) {   this.num = num; }
    public String getName() {   return name; }
    public void setName(String name) {  this.name = name; }
    public String getEmail() {  return email; }
    public void setEmail(String email) {    this.email = email; }
    public String getContents() {   return contents; }
    public void setContents(String contents) {  this.contents = contents; }
}

noticeBoardDAO.java我认为这里会发生错误。

public class noticeBoardDAO {// Controller

// DB Connection & Open
public static Connection loadOracleDriver() {
    Connection conn = null;
    try {
        conn = ConnectionHelper.getConnection("oracle");
    } catch (Exception e) {
        e.printStackTrace();
    }
    return conn;
}

// INSERT
public static void insert(Connection conn, noticeBoardVO vo) {
    StringBuffer sb = new StringBuffer();
    PreparedStatement pstmt = null;
    try {
        conn = ConnectionHelper.getConnection("oracle");
        sb.append("INSERT INTO noticebook(NUM, NAME, EMAIL, CONTENTS) ");
        sb.append(" VALUES(BOOK_NUM.NEXTVAL, ?, ?, ?) ");
        System.out.println(sb.toString());
        pstmt = conn.prepareStatement(sb.toString());
        pstmt.setString(1, vo.getName());
        pstmt.setString(2, vo.getEmail());
        pstmt.setString(3, vo.getContents());
        pstmt.executeUpdate(); //

    } catch (Exception e) {
        e.printStackTrace();
    }
}

mainWritePro.jsp(在用户单击SEND btn之后显示)

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert Page</title>
<link rel="stylesheet" type="text/css" href="../css/main.css">
</head>
<%
        request.setCharacterEncoding("utf-8");
%>
<body>

    <jsp:useBean id="vo" class="edu.kosta.vistorsPrac.noticeBoardVO"></jsp:useBean>
    <jsp:setProperty property="*" name="vo" />

    <%
    Connection conn = noticeBoardDAO.loadOracleDriver();
    noticeBoardDAO.insert(conn, vo);
    %>

    <h1>Successfully Inserted !</h1>
    <ul>
        <li><a href="#">DELETE</a></li>
        <li><a href="#">UPDATE</a></li>
        <li><a href="#">LIST</a></li>
    </ul>
</body>
</html>
java oracle sql-insert
1个回答
-1
投票
  • ORA-01400:无法将NULL插入(“ SCHEMA”。“ TABLE_NAME”。“ COLUMN_NAME”)]

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