我如何使用无服务器将多个端点部署到单个 lambda

Question

functions:
  ptDevices:
    name: ptDevices
    handler: dist/devices/serverless.handler
    timeout: 15 
    architecture: arm64
    events:
      - http:
          method: any
          path: /devices
      - http:
          method: any
          path: /devices/connections
      - http:
          method: any
          path: /devices/contexts
      - http:
          method: any
          path: /devices/datetodate
  

如何在一个 Lambda fybctuib 中添加所有路径并分别获取每个触发器的准确端点路径？

当我运行这个时，我得到：

/devices
 - any 
  /connections
   - any  
  /contexts
   - any 
  /datetodate
   - any

但在 Lambda 函数中，所有触发器只有一个 (

Trigger:https://qw735635.execute-api.us-east-2.amazonaws.com/dev/devices/contexts

)

我想要什么：

/devices
 - any (Trigger:https://qw735635.execute-api.us-east-2.amazonaws.com/dev/devices)
  /connections
   - any  (Trigger:https://qw735635.execute-api.us-east-2.amazonaws.com/dev/devices/connections)
  /contexts
   - any (Trigger:https://qw735635.execute-api.us-east-2.amazonaws.com/dev/devices/contexts)
  /datetodate
   - any (Trigger:https://qw735635.execute-api.us-east-2.amazonaws.com/dev/devices/datetodate)

表示一个 Lambda 函数中的所有 4 个触发器。

Answer 1

您可以添加多个具有不同名称的函数，指向同一个 lambda 函数，每个函数都有不同的端点。

这是您可以执行此操作的代码：

functions:
  ptDevices1:
    name: ptDevices1
    handler: dist/devices/serverless.handler
    timeout: 15 
    architecture: arm64
    events:
      - httpApi:
         path: /devices
         method: any   

  ptDevices2:
    name: ptDevices2
    handler: dist/devices/serverless.handler
    timeout: 15 
    architecture: arm64
    events:
      - httpApi:
         path: /devices/connections
         method: any  

  ptDevices3:
    name: ptDevices3
    handler: dist/devices/serverless.handler
    timeout: 15 
    architecture: arm64
    events:
      - httpApi:
         path: /devices/contexts
         method: any   

  ptDevices4:
    name: ptDevices4
    handler: dist/devices/serverless.handler
    timeout: 15 
    architecture: arm64
    events:
      - httpApi:
         path: /devices/datetodate
         method: any   

通过这种方式，您将获得您在所需输出中提到的单独端点。