父ID不保存在子表Spring JPA2 @OneToMany关系中

问题描述 投票:1回答:1

我有如下所示的json,它来自第三方服务,我通过开放假装客户端获得它。我试图使用Spring JPA2将这些细节保存到我的MySQL数据库中。

[
  {
    "request_id": 111,
    "name": "ABC",
    "groups": [
      {
        "id": 21,
        "group": "grp_A"
      },
      {
        "id": 22,
        "group": "grp_B"
      }
    ]
  },
  {
    "request_id": 222,
    "name": "ABC",
    "groups": [
      {
        "id": 23,
        "group": "grp_C"
      }
    ]
  },
  {
    "request_id": 333,
    "name": "ABC",
    "groups": [
      {
        "id": 24,
        "group": "grp_A"
      }
    ]
  },
  {
    "request_id": 444,
    "name": "ABC",
    "groups": [
      {
        "id": 25,
        "group": "grp_C"
      }
    ]
  },
  {
    "request_id": 555,
    "name": "ABC",
    "groups": []
  }
]

我已经为上面的json编写了映射,如图所示

requests.Java

@Entity
@Table(name = "requests")
@JsonIgnoreProperties(ignoreUnknown = true)
public class Requests {

    @Id
    @Column(name = "request_id")
    private String id;

    @Column(name = "name")
    private String name;

    @OneToMany(mappedBy = "id", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
    private Set<Groups> groups = Sets.newHashSet();

    // getters and setters
}

groups.Java

@Entity
@Table(name = "groups")
@JsonIgnoreProperties(ignoreUnknown = true)
public class Groups{

    @Id
    @Column(name = "id")
    private String id;

    @Column(name = "group")
    private String group;

    @ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    @JoinColumn(name = "request_id")
    private Requests requests;

    // getters and setters
}

现在在我的服务类中,我已经完成了如下所示的操作

List<Requests> allRequests = requestFeignClient.getRequests();
requestRepository.saveAll(allRequests);

所有细节都保存到数据库中,但request_id除外,如下所示。我的预期组表也显示如下

enter image description here

任何人都可以告诉我为什么request_id没有得到保存。

java spring-data-jpa jpa-2.0 spring-cloud-feign
1个回答
1
投票

尝试替换这个:

@OneToMany(mappedBy = "id", cascade = CascadeType.ALL, fetch = FetchType.LAZY)

有了这个:

@OneToMany(mappedBy = "requests", cascade = CascadeType.ALL, fetch = FetchType.LAZY)
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