JOLT 转换以过滤掉特定值/对象

Question

我想创建一个 JOLT 规范来过滤掉我需要的一切。

我有这个 JSON 输入：

{
  "StationDataList": {
    "StationData": {
      "ChannelData": [
        {
          "Values": {
            "VT": [
              {
                "t": "2023-12-13T00:15:00",
                "content": -1
              },
              {
                "t": "2023-12-13T00:30:00",
                "content": -2
              },
              {
                "t": "2023-12-13T00:45:00",
                "content": -3
              }
            ]
          },
          "channelId": "channelId1"
        },
        {
          "Values": {
            "VT": [
              {
                "t": "2023-12-13T01:00:00",
                "content": 1
              },
              {
                "t": "2023-12-13T02:00:00",
                "content": 2.5
              },
              {
                "t": "2023-12-13T03:00:00",
                "content": 3
              }
            ]
          },
          "channelId": "channelId2"
        }
      ],
      "timezone": "+01:00",
      "name": "stationName",
      "stationId": "123"
    }
  }
}

我想将每个 VT 对象提取到单独的对象中，并将字段 stationId、channelId、name 和 timezone 包含到每个对象中。

我昨天尝试了一整天，有很多不同的规格，但没有一个能提供我需要的输出。 目前我有这个规格：

[
  {
    "operation": "shift",
    "spec": {
      "StationDataList": {
        "StationData": {
          "ChannelData": {
            "*": {
              "Values": {
                "VT": {
                  "*": {
                    "@(5,stationId)": "[&4].stationId",
                    "@(5,timezone)": "[&4].timezone",
                    "@(5,name)": "[&4].name",
                    "@(3,channelId)": "[&4].channelId",
                    "t": "[&4].t",
                    "content": "[&4].content"
                  }
                }
              }
            }
          }
        }
      }
    }
  }
]

它返回我这个输出：

[ {
  "stationId" : [ "123", "123", "123" ],
  "timezone" : [ "+01:00", "+01:00", "+01:00" ],
  "name" : [ "stationName", "stationName", "stationName" ],
  "channelId" : [ "channelId1", "channelId1", "channelId1" ],
  "t" : [ "2023-12-13T00:15:00", "2023-12-13T00:30:00", "2023-12-13T00:45:00" ],
  "content" : [ -1, -2, -3 ]
}, {
  "stationId" : [ "123", "123", "123" ],
  "timezone" : [ "+01:00", "+01:00", "+01:00" ],
  "name" : [ "stationName", "stationName", "stationName" ],
  "channelId" : [ "channelId2", "channelId2", "channelId2" ],
  "t" : [ "2023-12-13T01:00:00", "2023-12-13T02:00:00", "2023-12-13T03:00:00" ],
  "content" : [ 1, 2.5, 3 ]
} ]

但我希望它们都是单独的对象，而不是全部在一个数组中，例如：

{
  "stationId" : "123",
  "timezone" : "+01:00",
  "name" : "stationName",
  "channelId" : "channelId1",
  "t" : "2023-12-13T00:15:00",
  "content" : -1
},
{
  "stationId" : "123",
  "timezone" : "+01:00",
  "name" : "stationName",
  "channelId" : "channelId1",
  "t" : "2023-12-13T00:30:00",
  "content" : -2
}
...

我怎样才能做到这一点？为什么他将所有内容添加到数组中而不是创建单独的对象？将不胜感激任何帮助。

Answer 1

由于 JSON 格式限制，没有数组包装器的独立对象是不可能的，但是如果需要将输出作为对象数组，那么您应该通过两个数组的索引来分隔对象层：

ChannelData

和

VT

，例如作为

[
  {
    "operation": "shift",
    "spec": {
      "*": {
        "*": {
          "*": {
            "*": {
              "*": {
                "VT": {
                  "*": {
                    "@5,stationId": "&4_&1.stationId",
                    "@5,timezone": "&4_&1.timezone",
                    "@5,name": "&4_&1.name",
                    "@3,channelId": "&4_&1.channelId",
                    "*": "&4_&1.&"
                  }
                }
              }
            }
          }
        }
      }
    }
  },
  {
    "operation": "shift",
    "spec": {
      "*": "[]"
    }
  }
]