我想为每个月创建列,如果该月位于两个日期之间,则将该月设置为 true。
例如,我的日期为= 2023-01-01,日期为= 2023-05-31
所以我希望 2023-02 列的值 = 1,因为本月位于这些日期之间
但是第 2023-06 列将得到值 = 0,因为本月超出范围。
现在我有桌子了
Customer nr Date from Date to
xxxxxx 2023-01-01 2023-05-31
yyyyyy 2023-03-01 2023-10-31
qqqqq 2023-08-01 2023-12-31
但我想要:
Customer nr Date from Date to 2023.01 2023.02 2023.03
xxxxxx 2023-01-01 2023-05-31 1 1 1
yyyyyy 2023-03-01 2023-10-31 0 0 1
qqqqq 2023-08-01 2023-12-31 0 0 0
如果
date_from
始终是该月的第一天,而 date_to
始终是该月的最后一天,则使用简单的 between
检查:
select *
, case when '2023-01-01' between date_from and date_to then 1 else 0 end as [2023-01]
, case when '2023-02-01' between date_from and date_to then 1 else 0 end as [2023-02]
, case when '2023-03-01' between date_from and date_to then 1 else 0 end as [2023-03]
from t;
否则,当使用范围重叠检查(包括开始和结束)时:
select *
, case when date_to >= '2023-01-01' AND date_from <= eomonth('2023-01-01') then 1 else 0 end as [2023-01]
, case when date_to >= '2023-02-01' AND date_from <= eomonth('2023-02-01') then 1 else 0 end as [2023-02]
, case when date_to >= '2023-03-01' AND date_from <= eomonth('2023-03-01') then 1 else 0 end as [2023-03]
from t;