“tuple[str, str]”类型的参数不能分配给“tuple[Literal, Literal]”类型的参数“__key”

Question

我是一个 python 新手，我一直在用 python 解决 Advent of Code 问题。然而，我在解决第2天的问题时遇到了问题。

我定义了一个

dict

将

tuple

映射到一个常量值。具体来说，我将

score_table

定义为：

        score_table = {('A', 'X'): 3, ('A', 'Y'): 6, ('A', 'Z'): 0,
                       ('B', 'X'): 0, ('B', 'Y'): 3, ('B', 'Z'): 6,
                       ('C', 'X'): 6, ('C', 'Y'): 0, ('C', 'Z'): 3}

但后来，当我尝试通过以下方式访问字典时，我收到了来自 pyright 的错误消息：

        for line in f:
            u, v = line.split()
            ans = ans + score[v] + score_table[(u, v)]

错误说

Argument of type "tuple[str, str]" cannot be assigned to parameter "__key" of type "tuple[Literal['A'], Literal['X']] | tuple[Literal['A'], Literal['Y']] | tuple[Literal['A'], Literal['Z']] | tuple[Literal['B'], Literal['X']] | tuple[Literal['B'], Literal['Y']] | tuple[Literal['B'], Literal['Z']] | tuple[Literal['C'], Literal['X']] | tuple[Literal['C'], Literal['Y']] | tuple[Literal['C'], Literal['Z']]" in function "__getitem__"
    Type "tuple[str, str]" cannot be assigned to type "tuple[Literal['A'], Literal['X']] | tuple[Literal['A'], Literal['Y']] | tuple[Literal['A'], Literal['Z']] | tuple[Literal['B'], Literal['X']] | tuple[Literal['B'], Literal['Y']] | tuple[Literal['B'], Literal['Z']] | tuple[Literal['C'], Literal['X']] | tuple[Literal['C'], Literal['Y']] | tuple[Literal['C'], Literal['Z']]"
      "tuple[str, str]" is incompatible with "tuple[Literal['A'], Literal['X']]"
        Tuple entry 1 is incorrect type
          "str" cannot be assigned to type "Literal['A']"
      "tuple[str, str]" is incompatible with "tuple[Literal['A'], Literal['Y']]"
        Tuple entry 1 is incorrect type
          "str" cannot be assigned to type "Literal['A']"
      "tuple[str, str]" is incompatible with "tuple[Literal['A'], Literal['Z']]" (reportGeneralTypeIssues)
1 error, 0 warnings, 0 informations 
Completed in 0.594sec

然而，我能够运行代码，甚至做对了问题。我做错了什么吗？

供参考，下面是我的整个程序

if __name__ == "__main__":
    with open("day2.in", "r", encoding="utf-8") as f:
        # A, X = rock, B, Y = paper, C, Z = scissors
        score = {'X': 1, 'Y': 2, 'Z': 3}
        score_table = {('A', 'X'): 3, ('A', 'Y'): 6, ('A', 'Z'): 0,
                       ('B', 'X'): 0, ('B', 'Y'): 3, ('B', 'Z'): 6,
                       ('C', 'X'): 6, ('C', 'Y'): 0, ('C', 'Z'): 3}
        ans = 0
        for line in f:
            u, v = line.split()
            ans = ans + score[v] + score_table[(u, v)]

        print(ans)

提前谢谢你！