我知道这里已经回答了这个问题(How do I return the response from an asynchronous call?,但是我找不到能满足我需要的任何东西。
我有一个基本函数,它从数据库读取数据,然后应该根据数据返回一个值。它是这样的:
function checkcooldown(name, user){
//gets the row from the sqlite database (returns a promise)
sql.get(`SELECT * FROM usercooldowns WHERE user = "${user}" AND name = "${name}"`).then((row) => {
if(!row || row == undefined){return 0} //if the user doesn't have a cooldown, return 0
else if(row.time <= getcurdate()){//if the cooldown is already over, return 0
return 0
}
else{//if a cooldown exists, return the number of seconds it lasts (currently dummy number)
return 123
}
})
}
我想在与此类似的if语句中调用此函数
if(await checkcooldown(name, user) > 0){//do something}
else{//add a new cooldown}
这当然不起作用,因为函数返回未定义。
但是,我在以上线程中找到的所有解决方案都没有帮助我,它们最终都使用了多行函数或解决了Promise。是否有任何方法可以使其紧凑到足以容纳上述简单的if语句?
感谢您的帮助^^
如果您想简洁,为什么不只使用async
await
语法?
async function checkcooldown(name, user) {
try {
const row = await sql.get(`SELECT * FROM usercooldowns WHERE user = "${user}" AND name = "${name}"`)
} catch(err) {
console.log(err)
}
if(row.time <= getcurdate()) {
return 0
} else {
return 123
}
}