我想创建一个Window
,重新声明它自己的DependencyProperty名为Content
。
public partial class InfoWindow : Window
{
public static new readonly DependencyProperty ContentProperty = DependencyProperty.Register("Content", typeof(object), typeof(InfoWindow), new PropertyMetadata(null));
public object Content
{
get { return GetValue(ContentProperty); }
set { SetValue(ContentProperty, value); }
}
}
并且XAML绑定此属性
<ContentControl Content="{Binding ElementName=_this, Path=Content}" />
它工作正常,只是Visual Studio Designer抱怨Logical tree depth exceeded while traversing the tree. This could indicate a cycle in the tree.
有没有办法告诉设计师绑定是InfoWindow.Content
而不是Window.Content
?或隐藏房产是一个坏主意,我应该重命名我的财产?
我在这里想要实现的是动态定义按钮的想法,这些按钮用于显示导航到不同表单的不同视图。 (见下文:)视图和视图模型之间的链接是在Dictionary View_ViewModel中设置的,用于标识按下按钮时为当前视图设置的视图。 (注意:我试图使用最基本的对象来避免使用IOC容器等,以便更容易理解代码)要记住的最重要的事情是正确设置DataContext,否则你将获得逻辑树深度遍历树时超出。错误。您可以在View后面的代码中或在XAML内部执行此操作。例:
public partial class SetupForm : UserControl
{
public SetupForm()
{
InitializeComponent();
DataContext = new SetupFormVM();
}
}
要么
<UserControl.DataContext>
<SaleVM:SalesEntryVM />
</UserControl.DataContext>
这是一个代码片段,可能会更清楚地解释它,并可能回答您的问题。视图模型定义了主窗口中所需的按钮和视图的数量。这是通过将ItemsControl绑定到View Model类中的列表来实现的。 Button命令受限于View Model类中的ICommand ChangeViewCommand属性,该类评估Button press和.calls ViewChange方法,该方法更改CurrentView(这绑定到XAML中的Content)
这就是我的主要Window xaml的样子。
<Window x:Class="MyNameSpace.Views.ApplicationWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:local="clr-namespace:MyNameSpace.Views"
mc:Ignorable="d"
Title="ApplicationWindow" Height="Auto" Width="Auto">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition /> -------------------> repeated five times
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition /> -------------------------> repeated five times
</Grid.RowDefinitions>
<DockPanel Grid.Row="0" Grid.Column="0" Grid.ColumnSpan="5" >
<!-- Bind to List of Pages -->
<ItemsControl ItemsSource="{Binding ControlItemsNamesList}" DockPanel.Dock="Top" >
<!-- Stack the buttons horizontally --> The list contains the labels to assign to the buttons
<ItemsControl.ItemsPanel>
<ItemsPanelTemplate> ---------------------------------------> This to stack the buttons Horizontally
<StackPanel Orientation="Horizontal" />
</ItemsPanelTemplate>
</ItemsControl.ItemsPanel>
<!-- This looks at the list items and creates a button with ControlName -->
<ItemsControl.ItemTemplate>
<DataTemplate>
<Button Content="{Binding ControlName}"
Command="{Binding DataContext.ChangeViewCommand, RelativeSource={RelativeSource AncestorType={x:Type Window}}}" ------> This is important for the Buttons to work Window or ContentControl.
CommandParameter="{Binding }"/>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
</DockPanel>
<ContentControl Grid.Row="1" Grid.Column="0" Grid.ColumnSpan="5" Grid.RowSpan="4" Content="{Binding CurrentView}"/> ---------> This is where I want the new Windows to appear when I click the button
</Grid>
当我单击主窗口中的按钮时,这就是我的用户控件xaml之一。
<UserControl x:Class="MyNameSpace.Views.SetupForm"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
mc:Ignorable="d"
d:DesignHeight="450" d:DesignWidth="800">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition /> ------------------- repeated five times
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition/> ------------------- repeated five times
</Grid.RowDefinitions>
<DockPanel Grid.Row="0" Grid.Column="0" Grid.RowSpan="5" Background="AliceBlue" Margin="0,0,0,0" >
<!-- Bind to List of Pages -->
<ItemsControl ItemsSource="{Binding ControlItemsNamesList}" DockPanel.Dock="Left" >
<!-- Stack the buttons horizontally -->
<ItemsControl.ItemsPanel>
<ItemsPanelTemplate>
<StackPanel Orientation="Vertical" />
</ItemsPanelTemplate>
</ItemsControl.ItemsPanel>
<!-- This looks at the list items and creates a button with ControlName -->
<ItemsControl.ItemTemplate>
<DataTemplate>
<Button Content="{Binding ControlName}"
Command="{Binding DataContext.ChangeViewCommand, RelativeSource={RelativeSource AncestorType={x:Type ContentControl}}}"
CommandParameter="{Binding }"/>
</DataTemplate>
</ItemsControl.ItemTemplate>
</ItemsControl>
</DockPanel>
<ContentControl Grid.Row="0" Grid.Column="1" Grid.ColumnSpan="5" Grid.RowSpan="4" Content="{Binding CurrentView}"/>
</Grid>
</UserControl>
这是主窗口的ViewModel:
using Products.MVVMLibrary;
using Products.MVVMLibrary.Interfaces;
using MyNameSpace.Views;
using System.Collections.Generic;
using System.Linq;
using System.Windows.Controls;
using System.Windows.Input;
namespace MyNameSpace.ViewModel
{
public class ApplicationVM : ObservableObject
{
private MyNameSpace IControlItem currentNavigationItem;
private MyNameSpace ContentControl currentView;
private MyNameSpace List<IControlItem> NavigationList;
private MyNameSpace ICommand changeViewCommand;
private MyNameSpace ViewConverter viewDictionary;
private MyNameSpace Dictionary<string, LinkViewToViewModel> View_ViewModel;
public ApplicationVM()
{
viewDictionary = new ViewConverter();
View_ViewModel = new Dictionary<string, LinkViewToViewModel>();
NavigationList = new List<IControlItem>();
InitialiseLists();
}
private MyNameSpace void AddControlNavigationItems(string name, ContentControl view, ObservableObject viewModel)
{
View_ViewModel.Add(name, new LinkViewToViewModel(view, viewModel));
IControlItem item = (IControlItem)viewModel;
NavigationList.Add(item);
}
private MyNameSpace void InitialiseLists()
{
AddControlNavigationItems("Sales", new SalesForm(), new SalesEntryVM());
AddControlNavigationItems("Purchases", new PurchaseEntryForm(), new PurchasesVM());
AddControlNavigationItems("Setup", new SetupForm(), new SetupFormVM());
//Use the property instead which creates the instance and triggers property change
CurrentViewModel = (IControlItem)View_ViewModel[View_ViewModel.Keys.ElementAt(0)].ViewModel;
CurrentView = View_ViewModel[View_ViewModel.Keys.ElementAt(0)].View;
}
public List<IControlItem> ControlItemsNamesList
{
get => NavigationList;
}
/// <summary>
/// Provides a list of names for Navigation controls to the control item
/// </summary>
public Dictionary<string, LinkViewToViewModel> ApplicationViews
{
get
{
return View_ViewModel;
}
set
{
View_ViewModel = value;
}
}
public ContentControl CurrentView
{
get
{
return currentView;
}
set
{
currentView = value;
OnPropertyChanged("CurrentView");
}
}
public IControlItem CurrentViewModel
{
get
{
return currentNavigationItem;
}
set
{
if (currentNavigationItem != value)
{
currentNavigationItem = value;
OnPropertyChanged("CurrentViewModel");
}
}
}
/// <summary>
/// This property is bound to Button Command in XAML.
/// Calls ChangeViewModel which sets the CurrentViewModel
/// </summary>
public ICommand ChangeViewCommand
{
get
{
if (changeViewCommand == null)
{
changeViewCommand = new ButtonClick(
p => ViewChange((IControlItem)p), CanExecute);
}
return changeViewCommand;
}
}
#region Methods
private MyNameSpace void ViewChange(IControlItem viewname)
{
foreach (KeyValuePair<string, LinkViewToViewModel> item in View_ViewModel)
{
if (item.Key == viewname.ControlName)
{//Set the properties of View and ViewModel so they fire PropertyChange event
CurrentViewModel = (IControlItem)item.Value.ViewModel;
CurrentView = item.Value.View;
break;
}
}
}
private MyNameSpace bool CanExecute()
{
return true;
}
#endregion
}
}
其他课程
public class LinkViewToViewModel
{
public LinkViewToViewModel(ContentControl view, ObservableObject viewModel)
{
View = view;
ViewModel = viewModel;
}
public ContentControl View { get; set; }
public ObservableObject ViewModel { get; set; }
}