如何在powershell中包含csv中所有数组对象的所有属性

问题描述 投票:0回答:4

我有一个 Powershell 脚本,可以读取一个文本文件,其中包含共享及其属性的单行描述。

然后,对于每个共享,将一个带有属性的对象添加到数组中。

我最终得到了一系列共享,其中许多具有共同属性,但也有一些仅出现在少数共享上。

当我将完成的数组通过管道传输到

Export-CSV
时,生成的 CSV 仅具有与数组中第一个对象的属性匹配的列。

感谢任何想法/帮助。

这是代码:

$shares_only = gc \\server\share\SHARES.txt | where {$_ -match '^*TYPE = DISK'}

$share_index = @()

$shares_only |foreach {

    $sharename = ($_.Split(" ")[1])
    $_ -match '\([\w\s.,"=<>()\/\*\+\-]*\);'|out-null

    $shareparams = $matches[0]

    $paramlist = ($shareparams.Substring(1,($shareparams.Length -3))).Split(",")

    $obj = $null
    $obj = New-Object System.Object

    $obj | Add-Member -type NoteProperty -Name NAME -Value $sharename

    $paramlist | foreach {
        $obj `
        | Add-Member -type NoteProperty -Name ($_.Split("=")[0]) -Value ($_.Split("=")[1])
    }
    $share_index += $obj
}

$share_index | Select * | Export-CSV -notype \\server\share\Shares.csv

这里以数组中的前两个对象为例(使用

$share_index[0..2]
输出到控制台):

NAME          : _ACCTEST_
TYPE          :  DISK 
PREFIX        :  (<USERCODE>) 
AREABYTES     :  184320 
ACCESS        :  ALL 
FAMILY        :  ACCTESTPACK 
DOWNSIZEAREA  :  TRUE 

NAME              : _HOME_
TYPE              :  DISK 
PREFIX            :  (<USERCODE>) 
COMMENT           :  Private user files 
AREABYTES         :  184320 
ACCESS            :  ALL -EXTRACT 
FAMILY            :  <FAMILY> 
DOWNSIZEAREA      :  TRUE 
ALLOWGUESTACCESS  :  TRUE 

这是 CSV 的前 3 行:

"NAME","TYPE ","PREFIX ","AREABYTES ","ACCESS ","FAMILY ","DOWNSIZEAREA "
"_ACCTEST_"," DISK "," (<USERCODE>) "," 184320 "," ALL "," ACCTESTPACK "," TRUE "
"_HOME_"," DISK "," (<USERCODE>) "," 184320 "," ALL -EXTRACT "," <FAMILY> "," TRUE "

您可以看到

COMMENT
ALLOWGUESTACCESS
属性丢失,即使它们位于
_HOME_
共享的数组中。

编辑:接受了@JPBlancs答案的稍微修改版本,所以我的代码的最后两行现在是:

$fixed_index = $share_index | Sort-Object -Property @{expression={(($_.psobject.Properties)|Measure-Object).count}} -Descending | ConvertTo-CSV -notype
$fixed_index | ConvertFrom-CSV | Sort -Property Name | Export-CSV -notype \\server\share\Shares.csv 

因此,按照建议完成,然后在新对象中转换为 CSV。 然后,将该对象从 CSV 转换回来,保留新属性,再次按名称排序以获得我需要的字母列表,然后再次导出到 CSV。

给我,例如:

"NAME","TYPE","PREFIX","PUBLIC","COMMENT","AREABYTES","ACCESS","FAMILY","DOWNSIZEAREA","ALLOWGUESTACCESS"
"_ACCTEST_"," DISK "," (<USERCODE>) ","",""," 184320 "," ALL "," ACCTESTPACK "," TRUE ",
"_HOME_"," DISK "," (<USERCODE>) ",""," Private user files "," 184320 "," ALL -EXTRACT "," <FAMILY> "," TRUE "," TRUE "
powershell csv properties
4个回答
4
投票

我做了这样的事

$a = "" | select "P1","P2"
$b = "" | select "P1","P2","P3"
$c = "" | select "P1","P2","P3","P4"
$array = $a,$b,$c
$array | Export-Csv c:\temp\t.csv

正如您所说:

#TYPE Selected.System.String
"P1","P2"
,
,
,

所以我们的想法是按属性计数对对象进行排序:

$array | Sort-Object -Property @{expression={$_.psobject.properties.count}} -Descending| Export-Csv c:\temp\t.csv

它给出:

#TYPE Selected.System.String
"P1","P2","P3","P4"
,,,
,,,
,,,

对于问题(创建对象并向 System.Object 添加成员),您可以使用:

Sort-Object -Property @{expression={(($_.psobject.Properties)|Measure-Object).count}} -Descending

4
投票

Export-Csv
ConvertTo-Csv
似乎仅采用发送给它们的对象之间的属性并集。我认为您必须解析文本文件并编译所有属性的列表,并且在创建对象时将任何缺少的属性值设置为 null。


1
投票

JPBlanc 的解决方案并不总是有效,因为最长的对象数组不必是较小数组的超集(例如,它不适用于下面所示的示例,其中所有对象都具有不同的属性,但数量没有差异属性)。

我通常可以按如下方式解决此问题:

$a = "" | select "P1","P2"
$b = "" | select "P2","P3"
$c = "" | select "P3","P4"
$array = $a,$b,$c
$array | Select ($array | ForEach {$_ | Get-Member -MemberType NoteProperty | Select -ExpandProperty Name} | Select -Unique) | Export-Csv ".\Union.csv"

不幸的是,这不适用于包含不同类型对象的 WMI 查询,但它适用于以下 cmdlet:

Function Union-Object {
    $Output = @()
    $Input | ForEach {
        If ($Output.Count) {$_ | Get-Member | Where {!($Output[0] | Get-Member $_.Name)} | ForEach {$Output[0] | Add-Member NoteProperty $_.Name $Null}}
        $Output += $_
    }
    $Output
}; Set-Alias Union Union-Object

用途:

$array | Union | Export-Csv ".\Union.csv"

另请参阅 GitHub 问题:#13906 将 -UnifyProperties 参数添加到 Select-Object


0
投票

我使用以下代码:

$a = "" | select "P1","P2"
$b = "" | select "P1","P2","P3"
$c = "" | select "P1","P2","P3","P4"
$props=@{n='P1';e={$_.p1}},@{n='P2';e={$_.p2}},@{n='P3';e={$_.p3}},@{n='P4';e={$_.p4}}
$array = $a,$b,$c
$array | select $props|Export-Csv c:\temp\t.csv
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