通过聚合显示不同的值

Question

我有一张表用于记录不同供应商的每日价格。我的目标是找到最好的（低价）供应商。 表结构是 表名称：lab1 列：ID、产品 ID、价格日期、价格、供应商

-----------------------------------------------------------------------------------
ID  Product_ID  Price_date  Price   Supplier
--------------------------------------------------------------------------------------
1   8           26-10-2014  1300    SP1
2   8           05-10-2014  1600    SP2
3   8           15-10-2014  1300    SP1
4   8           14-12-2014  1200    SP3
------------------------------------------------------------------------------------------

创建表结构

CREATE TABLE clickpic_pricecompare.lab1 (
  ID int(11) NOT NULL AUTO_INCREMENT,
  Product_ID int(11) DEFAULT NULL,
  Price_Date date DEFAULT NULL,
  Price decimal(19, 2) DEFAULT NULL,
  Supplier varchar(255) DEFAULT NULL,
  PRIMARY KEY (ID)
)
ENGINE = MYISAM
COMMENT = 'testing-purpose';

INSERT INTO  lab1(ID, Product_ID, Price_Date, Price, Supplier) VALUES
(1, 8, '2014-10-26', 1300.00, 'SP1');
INSERT INTO  lab1(ID, Product_ID, Price_Date, Price, Supplier) VALUES
(2, 8, '2014-10-05', 1600.00, 'SP2');
INSERT INTO  lab1(ID, Product_ID, Price_Date, Price, Supplier) VALUES
(3, 8, '2014-10-15', 1300.00, 'SP1');
INSERT INTO  lab1(ID, Product_ID, Price_Date, Price, Supplier) VALUES
(4, 8, '2014-10-14', 1200.00, 'SP3');

我需要如下所示的结果

--------------------------------------------------------------------------------------
ID  Product_ID  Month   Price   Supplier
--------------------------------------------------------------------------------------
4   8           October 1200    SP3
-------------------------------------------------------------------------------------------

请帮忙...

Answer 1

您可以使用自连接与产品 ID 和最低价格金额来获取每个产品 ID 的最低价格行

select l.ID,
l.Product_ID,
monthname(l.Price_Date) `Month`,
l.Price,
l.Supplier
from lab1 l
join (select Product_ID,min(Price) Price
     from lab1
     group by Product_ID) l1
using(Product_ID,Price)

演示

Answer 2

select temp2.id,
       temp2.Product_ID,
       DATENAME(month, temp2.Price_Date) AS MONTH,
       temp1.Min_Price,
       temp2.Supplier
from
(
     select Product_ID, min(Price) as Min_Price
     from lab1
     group  by Product_ID
) as temp1
inner join
lab1 temp2
on temp1.Product_ID = temp1.Product_ID
and temp1.Min_Price = temp2.Min_Price

Answer 3

我想您正在寻找：

选择 l.ID、l.Product_ID、月份名称（l.Price_Date）作为

Month

、l.Price、l.Supplier

from lab1 l join
     (select Product_ID, year(l.Price_date) as yr, month(l.Price_Date) as mon, min(Price) as Price
      from lab1
      group by Product_ID, year(l.Price_date), month(l.Price_Date)
     ) lmin
     on l.Product_id = lmin.Product_id and
        year(l.Price_Date) = lmin.yr and
        month(l.Price_Date) = lmin.mon;

如果您只需要 10 月份的数据，请添加

where

子句：

where l.Price_Date >= '2014-10-01' and l.Price_Date < '2014-11-01'