如何从PHP脚本在joomla 3.0中插入和发布新闻

问题描述 投票:1回答:2

我尝试从PHP脚本中插入一些文章,但我不明白。我需要知道哪些字段是必需的,以及如何创建查询才能做到这一点。

现在,我写下一个代码:

foreach($RSS_DOC->channel->item as $RSSitem){

    $alias    = md5($RSSitem->title);
    $fetch_date = date("Y-m-j G:i:s"); //NOTE: we don't use a DB SQL function so its database independent
    $item_title = $RSSitem->title;
    $item_description = $RSSitem->description;
    $item_date  = date("Y-m-j G:i:s", strtotime($RSSitem->pubDate));
    $item_url   = $RSSitem->link;

    // Does record already exist? Only insert if new item...

    $item_exists_sql = "SELECT alias FROM jos_content where alias = ".$alias;
    $item_exists = mysqli_query($enlace,$item_exists_sql);
    if(mysqli_num_rows($item_exists)<1){
        $mensaje = "<p>".$item_description."</p>Publicado: ".$item_date."<br/><a href='".$item_url."'>Ver noticia original</a>";
        $item_insert_sql = "INSERT INTO jos_content(title, alias, introtext, state, catid, created, created_by, access,featured) VALUES ('" .$item_title. "', '" . $alias. "', '" . $mensaje. "',1, 10,'".$fetch_date."',448,1,1)";
        $insert_item = mysqli_query($enlace,$item_insert_sql);

    }

}
php mysql joomla rss
2个回答
1
投票

首要任务是创建商品数据对象。我使用一种方法来清除现有的id或asset_id引用,以防我将文章数据从一个实例迁移到另一个实例。也可以用您的逻辑来代替,以构建商品数据对象。只要确保使用关联数组即可:

function processArticleData($obj) {
    $data = array();
    foreach ($obj as $key => $value) {
        $data[$key] = $value;
    }

    $data['id'] = 0;
    unset($data['asset_id']);

    return $data;
}

接下来,加载JTable内容类,绑定数据并保存。 Joomla完成了所有其余工作:

function addArticle($obj) {
    // Initialise variables;
    $data       = processModuleData($obj);
    $table      = &JTable::getInstance('content');

    // Bind the data.
    if (!$table->bind($data))
    {
        echo "<h1>Error Binding Article Data</h1>";
        return false;
    }

    // Check the data.
    if (!$table->check())
    {
        echo "<h1>Error Checking Article Data</h1>";
        return false;
    }

    // Store the data.
    if (!$table->store())
    {
        echo "<h1>Error Storing Article Data</h1>";
        return false;
    }

    return $table->get('id');
}

这种方法的好处是,它消除了对必填字段或潜在错误的任何“猜测”,就好像数据存在问题时,Joomla会抛出异常或错误说明问题所在。如果希望/需要获得真正的幻想,甚至可以加载JForm对象的内容,将数据绑定到该对象,然后在绑定到JTable对象之前进行验证。

创建数据对象只有两个要求。第一种是使用关联数组,第二种是所有键名都与#__content表中的列匹配。示例数据对象如下所示:

 $data = array(
    'title' => $title,
    'alias' => $alias,
    'introtext' => $introtext,
    'fulltext' => $fulltext,
    'catid' => $catid,
    'images' => '',
    'urls' => '',
    'attribs' => '',
    'metakey' => '',         
    'metadesc' => '',
    'metadata' => '',
    'language' => '',
    'xreference' => '',         
    'created' => JFactory::getDate()->toSql(),
    'created_by' => JFactory::getUser()->id,
    'publish_up' => JFactory::getDate()->toSql(),
    'publish_down' => JFactory::getDbo()->getNullDate(),
    'state' => 1
);

[我使用更多Joomla辅助函数使我的工作更轻松,但这应该为您提供一个很好的起点。

*编辑*

我改正了错字。不知道是否复制/粘贴但将下面的数组声明切换到下面的行并再次测试:

    $data       = processModuleData($obj);

0
投票

此脚本应执行此操作。...假定它存在于您网站的根目录中:

if (!defined('_JEXEC')) {
    define( '_JEXEC', 1 );
    define ('JPATH_BASE', 'c:\\wamp\\www\\mysiteroot');

    require_once ( JPATH_BASE .'/includes/defines.php' );
    require_once ( JPATH_BASE .'/includes/framework.php' );
    $mainframe = JFactory::getApplication('site');
}
function getContentTable($type = 'Content', $prefix = 'JTable', $config = array())
{
    return JTable::getInstance($type, $prefix, $config);
}
function addArticle($title, $alias)
{
    $table = getContentTable();
    $table->title = $title;
    $table->alias = $alias;
    $table->catid = 2;
    $table->state = 1;
    // and so on!
    // then save it
    $table->store();
}
$result = addArticle("foo", "bar");
© www.soinside.com 2019 - 2024. All rights reserved.