如何基于带有行和列标题的用户输入创建乘法表？

Question

需要让range（）值基于用户输入的任何内容作为开始和结束因素。它还需要行和列的标题。请使用简单的语法，我是编程新手！

# This program creates a multiplication table with nested loops and limits the
# factors based on user input values.
#
# References:
# https://www.youtube.com/watch?v=0rWHH5JfKdo
# https://www.youtube.com/watch?v=Dpkfh-hX4-M
# https://stackoverflow.com/questions/27312273/python-meaning-of-end-in-the-
# statement-print-t-end/27312325



def nested_loop(start, end):
    for i in range(start, end + 1):
        for j in range(start, end + 1):
            print(i * j, end='\t')
        print('')


def get_value(label):
    print("Enter " + label + " value:")
    value = int(input())
    return value


def main():
    start = get_value("starting")
    end = get_value("ending")
    nested_loop(start, end)


main()

Answer 1

您的代码已经完成了大部分工作，它在用户指定的时间段内打印了乘法表的二维矩阵，您只缺少可以像这样添加的标头部分

def nested_loop(start, end):
    # printing the top header
    print('', end='\t')
    for i in range(start, end + 1):
        print(i, end='\t')
    print('')

    for i in range(start, end + 1):
        print(i, end='\t') # printing the running column alongside the matrix
        for j in range(start, end + 1):
            print(i * j, end='\t')
        print('')


def get_value(label):
    print("Enter " + label + " value:")
    value = int(input())
    return value


def main():
    start = get_value("starting")
    end = get_value("ending")
    nested_loop(start, end)


main()

使用类似3, 10

程序输出：

    3   4   5   6   7   8   9   10  
3   9   12  15  18  21  24  27  30  
4   12  16  20  24  28  32  36  40  
5   15  20  25  30  35  40  45  50  
6   18  24  30  36  42  48  54  60  
7   21  28  35  42  49  56  63  70  
8   24  32  40  48  56  64  72  80  
9   27  36  45  54  63  72  81  90  
10  30  40  50  60  70  80  90  100 

Answer 2

同意接受的答案，但只需要显示python爱好者如何使事情复杂化……类似这样的东西：

def nasty_loop(start, end):
    print('\t'+'\t'.join(str(x) for x in range(start,end+1)))
    for y in range(start, end+1):
        print("%d\t" % y + '\t'.join(str(x*y) for x in range(start,end+1)))