为什么Python中的count()函数只允许'3个参数'以及如何克服

Question

有人能解释一下为什么我下面的特殊复杂代码不起作用吗？我尝试在谷歌上搜索，但找不到我理解的答案。显示错误，表明我的 count() 显然只允许“3 个参数”。所以想知道是否有一种简单的方法可以解决这个问题。我知道其中有一个“string.count”函数，但我似乎无法让它们工作。

非常感谢您花时间提供帮助！

print("Welcome to the Love Calculator")

name1 = input("What is your name?")

name2 = input("What is their name?")


name_1_lower_case = name1.lower()

name_2_lower_case = name2.lower()

both_names = name_1_lower_case + name_2_lower_case


calculate_true = both_names.count("t", "r", "u", "e")

calculate_love = both_names.count("l", "o", "v", "e")



total_score = str(calculate_true) + str(calculate_love)

print(total_score)

Answer 1

将代码更改为：

print("Welcome to the Love Calculator")

name1 = input("What is your name?")

name2 = input("What is their name?")


name_1_lower_case = name1.lower()

name_2_lower_case = name2.lower()

both_names = name_1_lower_case + name_2_lower_case

count_t = both_names.count("t")
count_r = both_names.count("r")
count_u = both_names.count("u")
count_e = both_names.count("e")
calculate_true = count_t + count_r + count_u + count_e

count_l = both_names.count("l")
count_o = both_names.count("o")
count_v = both_names.count("v")
calculate_love = count_l + count_o + count_v + count_e



total_score = str(calculate_true) + str(calculate_love)

print(total_score)

Answer 2

count 方法采用子字符串（或单个字符）来查找，以及可选的要搜索的索引的开头和/或结尾。您正在尝试向其发送大量不同的子字符串来查找。

您可能可以完成您想要的事情

total_score = sum( [ both_names.count( c ) for c in "true" + "love" ] )