使用节点数组创建JSON对象

问题描述 投票:2回答:3

我是一个表的结果,它给了我动态的字段层次结构,我需要用它来创建一个JSON对象。

EX:

[ [ 'request', 'cycleRange' ],
  [ 'request', 'cycleRange', 'from' ],
  [ 'request', 'cycleRange', 'to' ],
  [ 'request', 'cycleRange', 'to', 'month' ],
  [ 'request', 'cycleRange', 'to', 'year' ],
  [ 'request', 'datestmt' ],
  [ 'request', 'singleTran' ],
  [ 'request', 'singleTran', 'datePost' ],
  [ 'request', 'singleTran', 'dateTo' ] ]

我期望使用此示例创建的JSON对象应该是:

let expected = {
    request: {
        cycleRange: {
            from: null,
            to: {
                month: null,
                year: null
            }
        },
        datestmt: null,
        singleTran: {
            datePost: null,
            dateTo: null
        }
    }
};

我正在使用此函数来尝试构建对象,但我只是将最终数组作为对象:

let final = {};
for (let i of heirarchy) {
    assign(final, i, null);
}    

function assign(obj, keyPath, value) {
    let lastKeyIndex = keyPath.length - 1;
    let key;
    let i;

    for (i=0; i<lastKeyIndex; i++) {
        key = keyPath[i];

        if (!(key in obj)) {
            obj[key] = {};
        } else {
            if (i !== lastKeyIndex) {
                obj[key] = {};
            }
        }

        obj = obj[key];
    }

    obj[keyPath[lastKeyIndex]] = value;
}

目前我的结果我只得到:(我的源层次结构的最后一个索引)

{"request":{"singleTran":{"dateTo":null}}}

任何帮助,将不胜感激。

node.js json
3个回答
0
投票

因为obj引用final,这条线可能会让你恶作剧:

        obj = obj[key];

这将在hte循环的每次迭代中覆盖obj(在本例中为final)。我建议跟踪一个单独的变量,以便final保持不变异


0
投票

我有这个解决方案,但我认为有很多简化和改进的空间,我也用{}替换了null。

您可以使用lodash:https://lodash.com/docs/4.17.11#set中的_.set来替换我的示例中的set。

const array = [ [ 'request', 'cycleRange' ],
  [ 'request', 'cycleRange', 'from' ],
  [ 'request', 'cycleRange', 'to' ],
  [ 'request', 'cycleRange', 'to', 'month' ],
  [ 'request', 'cycleRange', 'to', 'year' ],
  [ 'request', 'datestmt' ],
  [ 'request', 'singleTran' ],
  [ 'request', 'singleTran', 'datePost' ],
  [ 'request', 'singleTran', 'dateTo' ] ];
  


const set = (path, obj) => path.split('.').reduce((o,i)=> {
     return o[i] ? o[i] : o[i] = {};
}, obj)

let myNewObject = {};
let path = '';

array.forEach(element => {
  path = '';
  element.forEach(key => {
     path = path ? path + '.' + key : key;
     set(path, myNewObject);
  });
});

console.log(myNewObject);

0
投票

我使用package deepmerge将各个结果合并到我的最终对象中

const deepmerge = require('deepmerge');
let final = {};
for (let i of heirarchy) {
    let temp = {};
    assign(temp, i, null);
    final = deepmerge(final, temp);
}
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