symfony 中的 Stripe 错误：请求未捕获的 PHP 异常 Stripe\Exception\InvalidRequestException：“不是有效的 URL”

Question

我在 symfony 中创建了这段代码：

    #[Route('/buy/{subjectId}', name: 'buy_subject', methods: ['POST'])]
    public function buySubject(Request $request, $subjectId, ManagerRegistry $managerRegistry, $stripeSK): Response
    {
        $entityManager = $managerRegistry->getManager();
        $subject = $entityManager->getRepository(Subject::class)->find($subjectId);
    
        error_log('Subject ID: ' . $subjectId);
    
        if (!$subject) {
            throw $this->createNotFoundException('Subject not found');
        }
    
        dump($subject);
    
        Stripe::setApiKey($stripeSK);
    
        error_log('Stripe API Key: ' . $stripeSK);
    
        $totalAmount = $subject->getSubjectPrice() ;
    
        error_log('Total Amount: ' . $totalAmount);
    
        $checkoutSession = Session::create([
            'payment_method_types' => ['card'],
            'line_items' => [[
                'price_data' => [
                    'currency' => 'usd',
                    'product_data' => [
                        'name' => $subject->getSubjectName(),
                    ],
                    'unit_amount' => $totalAmount,
                ],
                'quantity' => 1,
            ]],
            'mode' => 'payment',
            'success_url' => $this->generateUrl('subject_success'),
            'cancel_url' => $this->generateUrl('subject_cancel'),  
        ]);
    
    
        return $this->redirect($checkoutSession->url, 303);
    } 

仅出现此错误：

[申请] 4月30日 23:52:43 |CRITICA| REQUES 未捕获的 PHP 异常 Stripe\Exception\InvalidRequestException：“不是有效的 URL” C:\Users\user\Downloads\TW2.0-Starter-Project-main endor\stripe\stripe-php\lib\Exception\ApiErrorException.php 38号线

我希望点击“购买”按钮会将我带到条纹结账页面

Answer 1

因为您的实现使用

generateUrl

生成的 url 不会返回绝对 URL，仅返回绝对路径。

需要传递第三个参数来生成绝对URL

$this->generateUrl('subject_success', [], UrlGeneratorInterface::ABSOLUTE_URL);