Python-如何解析一个表格形状的字符串（带有-和+），以获取每个字段中的短语？ [关闭]

Question

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字符串输入如下：

              input_string: = """
+------------------------------------+-----------------------------------+
|title                               | title                             |
+------------------------------------+-----------------------------------+
| abcdabcdabc                        | abcdabcd, abcdabcdabcd, abcdabcda |
+------------------------------------+-----------------------------------+
| abcdabcdabcdabcdabcdabcdabcdabcda  | abcd abcddrama and abcdabcdabcdabD|
|                                    | to abcd abcd abc                  |
+------------------------------------+-----------------------------------+
    """

期望的输出是每个字段中按列划分的短语：
[
            (u'abcdabcdabc', u'abcdabcd, abcdabcdabcd, abcdabcda'),
            (u'abcdabcdabcdabcdabcdabcdabcdabcda', u"abcd abcddrama and abcdabcdabcdabD to abcd abcd abc")
]

Answer 1

input_string = """
+------------------------------------+-----------------------------------+
|title                               | title                             |
+------------------------------------+-----------------------------------+
| abcdabcdabc                        | abcdabcd, abcdabcdabcd, abcdabcda |
+------------------------------------+-----------------------------------+
| abcdabcdabcdabcdabcdabcdabcdabcda  | abcd abcddrama and abcdabcdabcdabD|
|                                    | to abcd abcd abc                  |
+------------------------------------+-----------------------------------+
    """

def reform(s):
    s1 = ""
    s2 = ""
    for i in range(len(s)):
        if (i%3) == 1:
            s1 += s[i].lstrip().rstrip() + " "
        if (i%3) == 2:
            s2 += s[i].lstrip().rstrip() + " "
    return s1.rstrip(), s2.rstrip()

sections = input_string.split("+\n")[2:4]
section_split = [x.replace("-","").replace("+","").split("|") for x in sections]

print([reform(x) for x in section_split])