使用 dayjs 和 React 来区分天数和月数的两个日期

Question

我的逻辑有点问题，我希望能够自动计算两个日期之间天数和/或月数的差异，例如：还剩 20 天，还剩 1 个月又 17 天，...函数直接用 dayjs 做这个，我似乎无法得到我想要的逻辑。

预先感谢您的帮助:)

暂时...

        let creation = dayjs(currentEstimate.createdAt)
        let limit_date = dayjs(currentEstimate.createdAt).add(currentEstimate.estimate_validation_date, 'd')

        let diff = dayjs(limit_date).diff(creation, 'd')

        let months = diff / 31
        if (months < 1){
            console.log(`devis valable ${diff} jours`)
        }else{
            console.log(`devis valable ${months} mois`)
        }

编辑

感谢斯蒂芬柯林斯 ->

let duration = require('dayjs/plugin/duration')
dayjs.extend(duration)
let relativeTime = require('dayjs/plugin/relativeTime')
dayjs.extend(relativeTime)

        dayjs(currentEstimate.createdAt).to(dayjs(currentEstimate.createdAt).add(currentEstimate.estimate_validation_date, 'd'), true)

//one month

Answer 1

我有一个类似的问题，我想展示

3 months and 5 days

而不仅仅是

3 months

.

我解决它的方法是创建一个自定义插件，但我已经将它修改为这个问题的辅助函数。

const detailedRelativeTime = (date: Dayjs) => {
  const now = dayjs()
  const duration = dayjs.duration(date.diff(now))

  // These values are whole numbers of each interval format
  const durationInYears = duration.years()
  const durationInMonths = duration.months()
  const durationInDays = duration.days()

  // We don't want to add suffixes to this variable since it will be used as the first part of modified outputs
  const relativeDate = date.fromNow(true)

  // Modify the years output if there is a year with at least 1 month
  // Using !== 0 because values can be negative
  if (durationInYears !== 0 && durationInMonths !== 0) {
    // Add the remaining months from the current date to get the leftover relative time
    // We use add() instead of subtract() because the duration variable can be negative if necessary
    const relativeLeftoverMonths = now.add(durationInMonths, 'months').fromNow()
    // e.g. 1 year and 5 months ago
    return relativeDate + ' and ' + relativeLeftoverMonths
  }

  // Modify the months output if there is a month with at least 1 day
  if (durationInMonths !== 0 && durationInDays !== 0) {
    const relativeLeftoverDays = now.add(durationInDays, 'days').fromNow()
    // e.g. 1 month and 5 days ago
    return relativeDate + ' and ' + relativeLeftoverDays
  }

  // There were no durations that need to be added, so just return the default relative date
  return date.fromNow()
}

你可以像这样使用这个功能：

detailedRelativeTime(dayjs('2019-01-01')) // 4 years and 4 months ago (at the time of writing)

Answer 2

**通过日期中的最大日期和最小日期**

enter code here

const minDate = new Date("2022-03-03"); const maxDate = new Date("2023-03-03");

let dD = Math.floor(new Date(maxDate - minDate) / (1000 * 60 * 60 * 24 ))

让 mD = maxDate.getMonth() - minDate.getMonth()

让 myD = maxDate.getYear() - minDate.getYear()

设 yD = 0

if(myD > 0){yD=myD*12}

mD += yD console.log(dD)console.log(mD)console.log(myD)