获取Google日历活动的eventID

问题描述 投票:0回答:1

我想借助谷歌脚本从特定事件中获取eventID。我正在使用这个变量:

function export_gcal_to_gsheet(){

// Reference Websites:
// https://developers.google.com/apps-script/reference/calendar/calendar
// https://developers.google.com/apps-script/reference/calendar/calendar-event
//

var mycal = "[email protected]";
var cal = CalendarApp.getCalendarById(mycal);
var today = new Date()
var thisweek = new Date (today.getTime())
var oneWeekfromNow = new Date(today.getTime() + (7*3600000*24));

//
var events = cal.getEvents(thisweek, oneWeekfromNow, {search: 'stammtisch'});

var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Termine");
// Uncomment this next line if you want to always clear the spreadsheet content before running - Note people could have added extra columns on the data though that would be lost
//sheet.clearContents();  

// Create a header record on the current spreadsheet in cells A1:N1 - Match the number of entries in the "header=" to the last parameter
// of the getRange entry below
var header = [["Event Title", "Event Start", "Thema", "LinkZoom", "EventID"]]
var range = sheet.getRange(1,1,1,5);
range.setValues(header);


// Loop through all calendar events found and write them out starting on calulated ROW 2 (i+2)
for (var i=0;i<events.length;i++) {
var row=i+2;
var myformula_placeholder = '';
// Matching the "header=" entry above, this is the detailed row entry "details=", and must match the number of entries of the GetRange entry below
// NOTE: I've had problems with the getVisibility for some older events not having a value, so I've had do add in some NULL text to make sure it does not error
  var details=[[events[i].getTitle(), Utilities.formatDate(events[i].getStartTime(),'Europe/Berlin', 'dd.MM.yyyy,\' um\' HH:mm\'Uhr\''), events[i].getDescription(), events[i].getLocation(), events[i].getId()]];

var range=sheet.getRange(row,1,1,5);
range.setValues(details);

}
}

但似乎getId与事件ID不同,因为当我将ID插入此链接时:https://www.google.com/calendar/event?eid= {event-id}&ctz = {timezone}

我收到一个错误。此外,当我手动共享我的事件时,我看到的ID与我从脚本中获取的ID不同。

希望有人可以帮助我。

google-apps-script google-sheets google-calendar-api
1个回答
1
投票

我知道你想要event-id使用https://www.google.com/calendar/event?eid={event-id}&ctz={timezone}。我的理解是否正确?如果我的理解是正确的,那么这个修改怎么样?

修改点:

  • 为了检索event-idhttps://www.google.com/calendar/event?eid={event-id}&ctz={timezone},您可以使用Calendar API的Calendar.Events.list()来检索它。

准备使用此修改后的示例脚本:

使用此修改后的脚本时,请在高级Google服务和API控制台中启用Calendar API。

Enable Calendar API v3 at Advanced Google Services

  • 在脚本编辑器上 资源 - >高级Google服务 打开Calendar API v3

Enable Calendar API at API console

  • 在脚本编辑器上 资源 - >云平台项目 查看API控制台 在“入门”中,单击“启用API”并获取密钥等凭据。 在左侧,单击“库”。 在搜索API和服务时,输入“日历”。然后单击Calendar API。 单击启用按钮。 如果已启用API,请不要关闭。 运行此脚本时,如果发生错误,可能需要等待几分钟,直到启用API。

修改后的脚本

function export_gcal_to_gsheet(){
  var mycal = "[email protected]";
  var cal = CalendarApp.getCalendarById(mycal);
  var today = new Date()
  var thisweek = new Date (today.getTime())
  var oneWeekfromNow = new Date(today.getTime() + (7*3600000*24));
  var events = cal.getEvents(thisweek, oneWeekfromNow, {search: 'stammtisch'});
  var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName("Termine");
  var header = [["Event Title", "Event Start", "Thema", "LinkZoom", "EventID"]]
  var range = sheet.getRange(1,1,1,5);
  range.setValues(header);

  // Added
  var items = Calendar.Events.list(mycal, {
    timeMin: thisweek.toISOString(),
    timeMax: oneWeekfromNow.toISOString(),
    q: 'stammtisch'
  }).items;

  for (var i=0;i<events.length;i++) {
    var row=i+2;
    var myformula_placeholder = '';
    var details=[[events[i].getTitle(), Utilities.formatDate(events[i].getStartTime(),'Europe/Berlin', 'dd.MM.yyyy,\' um\' HH:mm\'Uhr\''), events[i].getDescription(), events[i].getLocation(), items[i].htmlLink.split("=")[1]]]; // Modified
    var range=sheet.getRange(row,1,1,5);
    range.setValues(details);
  }
}

注意 :

  • 这个修改过的脚本从htmlLink中检索Calendar.Events.list()。链接是https://www.google.com/calendar/event?eid={event-id}。现在我从链接中检索event-id以使用items[i].htmlLink.split("=")[1]匹配您的脚本。如果您想要链接,请将其修改为items[i].htmlLink

参考文献:

如果我误解你的问题,我很抱歉。

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