我如何将这两个函数组合在一起，使我有一个约简

Question

第一个函数将所有GS应用于特定视图，第二个函数返回最高度。我怎样才能同时使用一个减少？

private getMap(): Array<ViewG> {
        const gW = ViewManager.getView().getGW();
        return gW.reduce((currentG, w) => {
            const GS = this.query.getAppliedGW(w);
            currentG.push([{ GS, priority:appliedGP[GS] }]);
            return currentG;
        }, []);
    }

    public getHighest(): ViewG {
        const entries = [...this.getMap()];
        if (entries.length !== 0) {
            const highestG = entries.reduce((prev, current) =>
                prev.priority > current.priority ? prev : current
            )[0];
            
            return highestG;
            }

Answer 1

public getHighest(): ViewG {
  //1. Take all GWs like in getMap()
  const gW = ViewManager.getView().getGW();

  //2. call .reduce() again to go over them
  return gW.reduce((prev, w) => {
    //3. transform to a GS 
    const GS = this.query.getAppliedGW(w);

    //4. instead of populating an array, just create the element
    const current = { GS, priority: appliedGP[GS] };

    //5. extract the previous priority in a null safe way:
    const prevPriority = prev?.priority ?? -Infinity;
    //                       ^          ^^ ^^^^^^^^^
    //                       |          ||     |
    // optional chaining -----          ||     |
    // nullish coalescing operator -------     |
    // fallback value in the case of null ------

    //5. compare with the previous one and return the higher priority
    return prev.priority > current.priority ? prev : current;
  }, null );
//   ^^^^ the default value
}