具有Yesod的可配置路径前缀

问题描述 投票:0回答:1

我有以下Web服务器:

{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE QuasiQuotes       #-}
{-# LANGUAGE TemplateHaskell   #-}
{-# LANGUAGE TypeFamilies      #-}
import           Data.Text        (Text)
import           Yesod

data App = App

mkYesod "App" [parseRoutes|
/      HomeR  GET
/link1 Link1R GET
/link2 Link2R GET
/link3 Link3R GET
/link4 Link4R GET
|]

instance Yesod App where

getHomeR :: Handler Html
getHomeR = defaultLayout $ do
    setTitle "Redirects"
    [whamlet|
        <p>
            <a href=@{Link1R}>Click to start the redirect chain!
    |]

getLink1R, getLink2R, getLink3R :: Handler ()
getLink1R = redirect Link2R -- /link2
getLink2R = redirect (Link3R, [("foo", "bar")]) -- /link3?foo=bar
getLink3R = redirect $ Link4R :#: ("baz" :: Text) -- /link4#baz

getLink4R :: Handler Html
getLink4R = defaultLayout
    [whamlet|
        <p>You made it!
    |]

main :: IO ()
main = warp 3000 App

但是我有来自诸如环境变量之类的路由前缀:

/prefix/      HomeR  GET
/prefix/link1 Link1R GET
/prefix/link2 Link2R GET
/prefix/link3 Link3R GET
/prefix/link4 Link4R GET

我如何实现?

我尝试过approot,但似乎不起作用...

haskell yesod template-haskell
1个回答
0
投票

我正在使用cleanPath删除前缀:

    cleanPath app s =
        if corrected == s
            then Right $ dropPrefix $ map dropDash s
            else Left corrected
      where
        corrected = filter (not . T.null) s
        dropDash t
            | T.all (== '-') t = T.drop 1 t
            | otherwise = t
        dropPrefix s' = case routePrefix $ appSettings app of
            Nothing -> s'
            Just prefix -> case headMay s' of
                            Just t -> if t == prefix then drop 1 s' else ["wrong prefix"]
                            Nothing -> ["wrong prefix"]

[如果您知道更好的方法,请评论或添加答案。谢谢!

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