分页和django过滤器

Question

我正在尝试使用分页实现搜索功能。我成功地设法让搜索工作或分页工作。但我无法弄清楚如何让他们两个同时一起工作。

这是.html，通过在.html中将object_list切换到filter.qs，我可以在正确搜索或正确分页之间切换。有人可以帮我修复代码，这样我就可以一起工作吗？

{% extends 'base.html' %}
{% load widget_tweaks %}
{% load my_tags %}

{% block head %}
    <title> Overview</title>
{% endblock %}
{% block content %}
    <form method="get">
        <div class="jumbotron">
            <h4 style="margin-top: 0">Filter</h4>
            <div class="row">
                <div class="form-group col-sm-4 col-md-3">
                    {{ filter.form.name.label_tag }}
                    {% render_field filter.form.name class="form-control" %}
                </div>
                <div class="form-group col-sm-4 col-md-3">
                    {{ filter.form.city_location.label_tag }}
                    {% render_field filter.form.city_location class="form-control" %}
                </div>
            </div>
            <button type="submit" class="btn btn-primary">
                <span class="glyphicon glyphicon-search"></span> Search
            </button>
        </div>
    </form>


<table class="table table-bordered">
    <thead>
    <tr>
        <th>Name</th>
        <th>City Location</th>
    </tr>
    </thead>
    <tbody>
    {% for object in object_list %}
        <tr>
            <td>{{ object.name }}</td>
            <td>{{ object.city_location }}</td>

        </tr>
    {% empty %}
        <tr>
            <td colspan="5">No data</td>
        </tr>
    {% endfor %}
    </tbody>
</table>
<br>
<br>


<div id="footer">
    <div class="container text-center">
        <p class="text-muted credit" style="color:#fff">
            {% if is_paginated %}
                {% if page_obj.has_previous %}
                    <a href="?{% param_replace page=1 %}">First</a>
                    {% if page_obj.previous_page_number != 1 %}
                        <a href="?{% param_replace page=page_obj.previous_page_number %}">Previous</a>
                    {% endif %}
                {% endif %}
                Page {{ page_obj.number }} of {{ paginator.num_pages }}
                {% if page_obj.has_next %}
                    {% if page_obj.next_page_number != paginator.num_pages %}
                        <a href="?{% param_replace page=page_obj.next_page_number %}">Next</a>
                    {% endif %}
                    <a href="?{% param_replace page=paginator.num_pages %}">Last</a>
                {% endif %}

                <p>Objects {{ page_obj.start_index }}—{{ page_obj.end_index }}</p>
            {% endif %}
    </div>
</div>

{% endblock %}

这是我的模特

from django.db import models


# Create your models here.
class lab(models.Model):
    name = models.CharField(max_length=255)
    city_location = models.CharField(max_length=255)


    def __str__(self):
        return self.Lab_name

这是我的views.py

class labListView(LoginRequiredMixin, ListView):
    context_object_name = "Lab_folders"
    model = lab
    template_name = "researcher_view_app/Lab_overview.html"
    paginate_by = 20

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['filter'] = labOverviewFilter(self.request.GET, queryset=self.get_queryset())

        return context

这是我的filters.py

import django_filters


class labOverviewFilter(django_filters.FilterSet):
    Lab_name = django_filters.CharFilter(lookup_expr='icontains')
    Lab_city_location = django_filters.CharFilter(lookup_expr='icontains')

而我不知道的部分，我不知道如何修改但是有效的是：我的tempatetag

app_name/templatetags/my_tags.py

from django import template

register = template.Library()


@register.simple_tag(takes_context=True)
def param_replace(context, **kwargs):
    """
    Return encoded URL parameters that are the same as the current
    request's parameters, only with the specified GET parameters added or changed.

    It also removes any empty parameters to keep things neat,
    so you can remove a parm by setting it to ``""``.

    For example, if you're on the page ``/things/?with_frosting=true&page=5``,
    then

    <a href="/things/?{% param_replace page=3 %}">Page 3</a>

    would expand to

    <a href="/things/?with_frosting=true&page=3">Page 3</a>

    Based on
    https://stackoverflow.com/questions/22734695/next-and-before-links-for-a-django-paginated-query/22735278#22735278
    """
    d = context['request'].GET.copy()
    for k, v in kwargs.items():
        d[k] = v
    for k in [k for k, v in d.items() if not v]:
        del d[k]
    return d.urlencode()

Answer 1

您可以在get_queryset方法中应用过滤器。像这样

class labListView(ListView):
    context_object_name = "Lab_folders"
    model = lab
    template_name = "researcher_view_app/Lab_overview.html"
    paginate_by = 20

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['filter'] = labOverviewFilter(self.request.GET, queryset=self.get_queryset())
        return context

    def get_queryset(self):
        qs = super().get_queryset()
        word = labOverviewFilter(self.request.GET, queryset=qs)
        return word.qs

获取查询集后，分页逻辑起作用。因此，为分页器提供过滤的查询集。