仅选择一行时获取总行号

Question

相关/类似问题：MySQL - Get row number on select，Select only partial result but get total number of rows

我目前有这张桌子：

+----+--------------------+---------------+--------+
| id | accountId          | competitionId | rating |
+----+--------------------+---------------+--------+
|  1 | theidoftheaccount1 |            1  | 100    |
|  2 | theidoftheaccount2 |            3  | 90     |
|  3 | theidoftheaccount3 |            1  | 80     |
|  4 | theidoftheaccount4 |            1  | 50     |
+----+--------------------+---------------+--------+

我想用accountId='theidoftheaccount3'获取行，所以我调用通常的SQL语句SELECT * FROM competitors WHERE competitionId='someotherid1' AND accountId='theidoftheaccount3 ' ORDER BY rating DESC，一切都很好。

问题：现在，我想知道我所得到的行的行号，但只知道所有其他具有competitionId='someotherid1'的行。该行号将是同一竞争中所有其他竞争对手中竞争对手的“排名”。

所以基本上在一天结束时我会回来：

+----+--------------------+---------------+--------+-----------+
| id | accountId          | competitionId | rating | rowNumber |
+----+--------------------+---------------+--------+-----------+
|  3 | theidoftheaccount3 |            1  | 80     | 2         |
+----+--------------------+---------------+--------+-----------+

如何完成？

Answer 1

一种方法是在子查询中使用row_number()：

select c.*
from (select c.*,
             rank() over (partition by competitionid order by rating desc) as ranking
      from competitors c
      where competitionId = 'someotherid1'
     ) c
where accountId = 'theidoftheaccount3';