MySQL日期字段未响应查询中的ASC或DESC

Question

我正在尝试按升序或降序对日期表进行排序，但我都无法执行它。该查询未给出语法错误，因此我认为不是。

Server version: 5.7.28-0ubuntu0.18.04.4 (Ubuntu)

Copyright (c) 2000, 2019, Oracle and/or its affiliates. All rights reserved.

mysql> select * from elections order by 'last_election' ASC;
+--------+-----------------+---------------+
| row_id | jurisdiction_id | last_election | 
+--------+-----------------+---------------+
|      1 |               3 | 2018-11-24    |
|      2 |               2 | 2019-03-23    |
|      4 |               5 | 2018-03-17    |
|      5 |               4 | 2017-11-25    |
|      6 |               1 | 2016-10-15    |
|      7 |               6 | 2017-03-11    |
|      8 |               7 | 2018-03-03    | 
|      9 |               8 | 2016-08-27    | 
|     11 |               9 | 2019-05-18    | 
+--------+-----------------+---------------+
9 rows in set (0.00 sec) 

上一个/其他类似的问题都说，“您的字段类型是文本还是varchar ，,！”但是字段类型绝对是日期：

+----------------------+---------+------+-----+---------+----------------+
| Field                | Type    | Null | Key | Default | Extra          |
+----------------------+---------+------+-----+---------+----------------+
| row_id               | int(11) | NO   | PRI | NULL    | auto_increment |
| jurisdiction_id      | int(11) | NO   | UNI | NULL    |                |
| last_election        | date    | YES  |     | NULL    |                |
+----------------------+---------+------+-----+---------+----------------+

我如何查询表以便last_election正确？

Answer 1

似乎您的日期列不是日期时间类型。排序时必须将其转换为日期时间：

select * from elections order by CONVERT(datetime, last_election) ASC;

尝试这个。希望它能解决您的问题