有没有任何方法可以将图像作为变量从php传递给python脚本

Question

我将base64编码的图像字符串传递给python脚本时出错...无法运行shell_execute（“python hello.py $ data”）这是我的代码

php文件

 <?php
 echo "Good Work";
 $img = file_get_contents("aaaa.jpg");
 $data = base64_encode($img);
 $output = shell_exec("python hello.py".$data);
 echo $output;
 ?>

hello.py文件

import sys
import base64
image_64_encode=sys.argv[1]
with open("image.jpg","wb") as fh:
     fh.write(base64.decodebytes(image_64_encode))`

Answer 1

执行此操作的最佳方法是将base64写入单独的文件，以便不需要编码。我稍微修改了您的代码以反映这一点。

PHP文件

<?php
$img = file_get_contents("image.jpg");
$data = base64_encode($img);
$content = $data;
$file = "myFile.base64";
$fp = fopen($file,"wb");
fwrite($fp,$content);
fclose($fp);

$output = shell_exec("python hello.py $file");
echo $output;
?>

PYTHON文件

import sys
import base64
file=sys.argv[1]
f = open(file)
base_64 = f.read()

# print (base_64)
# Do what you want with the base_64 variable.

image_64_encode=base_64
with open("image.jpg","wb") as fh:
   fh.write(base64.decodebytes(image_64_encode))