此shell脚本做什么？

Question

请帮助我了解此Shell脚本的作用：

# main
for HOST in ${HOSTS}
do
URI=http://${HOST}:80
count=99
result=`/opt/splunk/bin/splunk search "index=${INDEX} sourcetype=${SOURCETYPE} SPLUNK_HEALTH_CHECK |stats count" -earliest_time ${EARLIEST} -latest_time ${LATEST} -uri ${URI} -auth ${USER}:${PASS} -preview F -output csv -timeout ${TIMEOUT} 2>&1 |grep -v count |tr -d '\n' |sed 's/"//g'`
if expr $result : '[0-9]*' > /dev/null 2>&1; then

count=$result
result="OK"
fi
date +"%Y-%m-%d %T sh=${HOST} status=\"${result}\" delay_status=$count"
done

从splunk调用此脚本时，出现以下错误：

status =“无法查询HOME变量。不能使用Auth令牌已缓存。10“ delay_status = 99

Answer 1

Could not look up HOME variable. Auth tokens cannot be cached

[root用户或权限设置不正确，尝试运行Splunk时通常会发生此错误。在您的情况下，您正在将USER和PASS传递到脚本中，但是bash不能正确扩展这些值（请参见https://answers.splunk.com/answers/446944/getting-error-could-not-look-up-home-variable-auth.html）。