两个矩形之间的距离

Question

如何找到两个矩形之间的距离？相交的距离应返回0。

Answer 1

这是一个快速函数，用于计算由CGSize表示的两个CGRect之间的距离：

CGSize CGSizeDistanceBetweenRects(CGRect rect1, CGRect rect2)
{
    if (CGRectIntersectsRect(rect1, rect2))
    {
        return CGSizeMake(0, 0);
    }

    CGRect mostLeft = rect1.origin.x < rect2.origin.x ? rect1 : rect2;
    CGRect mostRight = rect2.origin.x < rect1.origin.x ? rect1 : rect2;

    CGFloat xDifference = mostLeft.origin.x == mostRight.origin.x ? 0 : mostRight.origin.x - (mostLeft.origin.x + mostLeft.size.width);
    xDifference = MAX(0, xDifference);

    CGRect upper = rect1.origin.y < rect2.origin.y ? rect1 : rect2;
    CGRect lower = rect2.origin.y < rect1.origin.y ? rect1 : rect2;

    CGFloat yDifference = upper.origin.y == lower.origin.y ? 0 : lower.origin.y - (upper.origin.y + upper.size.height);
    yDifference = MAX(0, yDifference);

    return CGSizeMake(xDifference, yDifference);
}

Answer 2

有点相关的注释，这是如何计算两个给定CGRect的centers>]之间的距离：

CGFloat CGRectGetDistanceBetweenCenters( CGRect rect1, CGRect rect2 )
{
   CGPoint center1 = CGPointMake( CGRectGetMidX( rect1 ), CGRectGetMidY( rect1 ) );
   CGPoint center2 = CGPointMake( CGRectGetMidX( rect2 ), CGRectGetMidY( rect2 ) );

   CGFloat horizontalDistance = ( center2.x - center1.x );
   CGFloat verticalDistance = ( center2.y - center1.y );

   CGFloat distance = sqrt( ( horizontalDistance * horizontalDistance ) + ( verticalDistance * verticalDistance ) );

   return distance;
}
    

Answer 3

向批准的答案添加快速版本：