java.time.format.DateTimeParseException:无法解析文本'2019-02-16 09:29:32.959',在索引10处找到未解析的文本

问题描述 投票:0回答:2

我在MySQL中有一个类型时间戳包含“2019-2-16 8:00:00”的列,我今天使用spring boot来获取本地并与之进行比较。我在google上做了很多搜索,但没有任何帮助。这是我的最终代码:

   @Override
public List<TaskDTO> getTodayTask(int employeeID) {
    Date today = getToday();
    List<Task> listOfTask = taskRepository.findByAssigneeIdAndAndStartTime(employeeID, today);
    List<TaskDTO> listOfDTO = new ArrayList<>();
    for (Task t : listOfTask) {
        listOfDTO.add(taskMapper.toDTO(t));
    }
    return listOfDTO;
}


private Date getToday() {
    Calendar calendar = Calendar.getInstance();

    Timestamp timestamp = new Timestamp(calendar.getTime().getTime());

    DateTimeFormatter format = DateTimeFormatter.ofPattern("yyyy-MM-dd");

    OffsetDateTime odt = OffsetDateTime.parse ( timestamp.toString() , format );

    Instant instant = odt.toInstant();

    return Date.from(instant);
}

和我的存储库:

    @Query("SELECT i FROM Task i WHERE i.assigneeId = ?1 and CAST( i.startTime as date) = ?2")
List<Task> findByAssigneeIdAndAndStartTime(int assigneeID, Date startTime);

我发现java.util.Date已被弃用,所以我试图找到另一种方式。

我的实体:

@Entity

@Table(name =“task”)public class Task实现Serializable {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private Long id;

@Column(name = "title")
private String title;

@Column(name = "assigner_employee_id")
private int assignerId;

@Column(name = "assignee_employee_id")
private int assigneeId;

@Column(name = "workplace_id")
private int workplaceId;

@Column(name = "schedule_id")
private Long scheduleId;

@Column(name = "start_time")
private Timestamp startTime;

@Column(name = "end_time")
private Timestamp endTime;

@Column(name = "check_in_time")
private Timestamp checkInTime;

@Column(name = "attendance_status")
private Integer attendanceStatus;

@Column(name = "status")
private Integer status;

@Column(name = "date_create")
private Timestamp dateCreate;

@Column(name = "priority")
private Integer priority;

@Column(name = "description")
private String description;

public Long getId() {
    return id;
}

public void setId(Long id) {
    this.id = id;
}

public String getTitle() {
    return title;
}

public void setTitle(String title) {
    this.title = title;
}

public void setAssignerId(int assignerId) {
    this.assignerId = assignerId;
}

public void setAssigneeId(int assigneeId) {
    this.assigneeId = assigneeId;
}

public int getAssignerId() {
    return assignerId;
}

public int getAssigneeId() {
    return assigneeId;
}

public int getWorkplaceId() {
    return workplaceId;
}

public void setWorkplaceId(int workplaceId) {
    this.workplaceId = workplaceId;
}

public Long getScheduleId() {
    return scheduleId;
}

public void setScheduleId(Long scheduleId) {
    this.scheduleId = scheduleId;
}

public Integer getAttendanceStatus() {
    return attendanceStatus;
}

public void setAttendanceStatus(Integer attendanceStatus) {
    this.attendanceStatus = attendanceStatus;
}

public Integer getStatus() {
    return status;
}

public void setStatus(Integer status) {
    this.status = status;
}

public Integer getPriority() {
    return priority;
}

public void setPriority(Integer priority) {
    this.priority = priority;
}

public String getDescription() {
    return description;
}

public void setDescription(String description) {
    this.description = description;
}

public Timestamp getStartTime() {
    return startTime;
}

public void setStartTime(Timestamp startTime) {
    this.startTime = startTime;
}

public Timestamp getEndTime() {
    return endTime;
}

public void setEndTime(Timestamp endTime) {
    this.endTime = endTime;
}

public Timestamp getCheckInTime() {
    return checkInTime;
}

public void setCheckInTime(Timestamp checkInTime) {
    this.checkInTime = checkInTime;
}

public Timestamp getDateCreate() {
    return dateCreate;
}

public void setDateCreate(Timestamp dateCreate) {
    this.dateCreate = dateCreate;
}

}

我收到一个错误:

java.time.format.DateTimeParseException:无法解析文本'2019-02-16 09:29:32.959',在索引10处找到未解析的文本

我做了很多搜索,但仍然没有找到合适的答案。谢谢。

java spring-boot datetime timestamp
2个回答
1
投票

你是正确的,而不仅仅是那个。虽然尚未正式弃用,但DateCalendarTimestamp这些类已经过时了,由于它们的设计问题,我们不应该使用它们。

我不是Spring Boot用户,不知道传递给查询的是什么,而不是老式的Date。我非常希望使用java.time API中的一种现代类型(OffsetDateTimeInstantDateTimeFormatter所属的)存在更现代的解决方案。如果你只需要通过一个日期,而不是一天中的时间,那么LocalDate将是合乎逻辑的,但正如我所说,我不知道。

如果您必须为Spring Boot查询需要Date

private static Date getToday() {
    Instant instant = Instant.now();
    return Date.from(instant);
}

您的代码出了什么问题?要解析为OffsetDateTime,您的日期时间字符串和格式模式字符串不仅需要指定日期,还需要指定时间和UTC偏移量(或者您需要以其他方式提供它们)。在你的代码中,OffsetDateTime成功地将2019-02-16解析为yyyy-MM-dd,并且因为格式模式不长,所以它抱怨来自Timestamp.toString的字符串是。但是,缩短字符串是没有用的,因为那时一天的时间会丢失,并且无论如何UTC的偏移都会,所以它无法工作。


0
投票

问题在于您使用的模式。试试这个:-

DateTimeFormatter format = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSS");

代替:-

DateTimeFormatter format = DateTimeFormatter.ofPattern("yyyy-MM-dd");
© www.soinside.com 2019 - 2024. All rights reserved.