c#如果计时器的当前时间大于

问题描述 投票:0回答:1

我收到一个gRPC响应流,如果在500ms后没有收到消息,我想调用一个动作。我打算使用秒表类,但它更适合调试,我担心它可能不是最有效的方法。我想在现有方法中做一些事情:

while (await streamingCall.ResponseStream.MoveNext(
                    default(CancellationToken)))
                {

                }

这样:

while (await streamingCall.ResponseStream.MoveNext(
                    default(CancellationToken)))
                {
                    //Message received
                    //Begin some sort of timer
                    //If no other message has been received for 500ms, execute ExampleMethod()
                }
c# timer stream grpc ienumerator
1个回答
0
投票

每当收到消息时,您可以将DateTime分配给变量,并在Timer中从中减去旧时间,以查看自上次消息以来经过了多长时间:

DateTime LastMsgTime = DateTime.MinValue;
Timer timer = new Timer { Interval = 50, Enabled = false };
timer.Tick += (s,e) => 
{ 
    if((DateTime.Now- LastMsgTime).TotalMilliSeconds > 500)  
       {ExampleMethod(); timer.Enabled = false; }
};
while (await streamingCall.ResponseStream.MoveNext(
                    default(CancellationToken)))
                {
                     LastMsgTime = DateTime.Now;
                    //Message received
                    timer.Enabled = true;
                }
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