不要忽略外部点击弹出窗口

问题描述 投票:0回答:1

我有一个弹出窗口,希望以编程方式进行充气和关闭,我不希望任何用户输入都将其关闭。但是,当触摸弹出式屏幕之外的屏幕时,弹出式窗口被关闭了,我知道这个问题已经被问过了,但是我已经尝试了发现的每个变体,但似乎无法使它工作……这是我的代码:

LayoutInflater inflater = (LayoutInflater)
                mContext.getSystemService(LAYOUT_INFLATER_SERVICE);
        View popupView = inflater.inflate(R.layout.custom_loading, null);
        int width = LinearLayout.LayoutParams.WRAP_CONTENT;
        int height = LinearLayout.LayoutParams.WRAP_CONTENT;
        boolean focusable = false;
        popupWindow = new PopupWindow(popupView, width, height, focusable);
        popupWindow.setElevation(20);
        popupWindow.setBackgroundDrawable(ContextCompat.getDrawable(mContext, R.drawable.transparent_back));
        popupWindow.setTouchable(true);
        popupWindow.setOutsideTouchable(true);
        popupWindow.setTouchInterceptor((View view, MotionEvent motionEvent) -> {return false;});
        popupWindow.showAtLocation(v, Gravity.CENTER, 0, 0);// v is a view passed as a parameter to the function

谢谢! :)

java android popupwindow
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popupWindow.setOutsideTouchable(false);
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