我的函数不能在 kotlin 中正确访问参数？

Question

我正在从这个页面做一个简单的石头、剪刀、布、蜥蜴和斯波克问题https://retosdeprogramacion.com/semanales2023

我创建了一个函数调用 whoWins()，如果玩家 1 获胜，它基本上返回下一个字符串“P1”，如果玩家 2 获胜则返回“P2”或“Tie”……你知道在什么情况下 XD

fun whoWins(game: Array<String>): String {
    
    var chooseP1 = game.get(0)
    var chooseP2 = game.get(1)
    
    println("Choose is ok : $chooseP1 and the type is: "+ chooseP1::class.simpleName)
    println("Choose is ok : $chooseP2 and the type is: "+ chooseP2::class.simpleName)
    
    var rules: MutableMap<String, ArrayList<String>> = mutableMapOf(
        "rock" to arrayListOf("scissors", "lizard"),
        "scissors" to arrayListOf("paper", "lizard"),
        "lizard" to arrayListOf("spock", "paper"),
        "paper" to arrayListOf("spock", "rock"),
        "spock" to arrayListOf("scissors", "rock")
    )
    
    if (chooseP1 == chooseP2) return "Tie"
    
    println("\nhere for some reason it returns null, HELP! "+ rules[chooseP1]+"\n")
    
    rules[chooseP1]?.forEach {
        if (it == chooseP2) {
            return "P1"
        }
    }
    
    return "P2"
    
}

出于某种原因，当我尝试使用 var 访问地图时，系统返回 null，

现在为了保存我游戏的不同回合，问题使用数组，但是当我访问方法时

whoWins()

系统总是返回“P2”，但是当我使用函数中直接声明的字符串方法时它起作用了好的，这是我的主要功能

fun main(args: Array<String>) { 
    
    var game1 = mapOf<String, Array<String>>( "round1" to arrayOf("🗿rock", "scissors️"), "round2" to arrayOf("scissors️", "rock🗿"), "round3" to arrayOf("📄paper", "scissors️") ) 
    
    var game2 = arrayOf( arrayOf("🗿rock", "scissors️"), arrayOf("scissors️", "rock🗿"), arrayOf("📄paper", "scissors️"), arrayOf("🗿spock", "scissors️"), arrayOf("lizard️", "spock"), arrayOf("📄spock", "rock️") )
    
    println("the var  ${game1.get("round1")!!.get(0)} type is: "+game1.get("round1")!!.get(0)::class.simpleName)
    
    println("Game 1 " + whoWins(game1.get("round1")!!))
    println("Game 2 " + whoWins(game2.get(0)!!))
    println("But the function is working fine: " + whoWins(arrayOf("rock", "scissors")))
    /*
        for (game in game2){
            if(whoWins(game.get(0),game.get(1)) == "P1"){
                pointsP1++
            }else{
                pointsP2++
            }
        }
    
        println(
            if (pointsP1 == pointsP2) "Tie"
            else if (pointsP1 > pointsP2) "Player 1"
            else "Player 2"
        )
    */
}

在这种情况下，函数应该在这种特定情况下返回“P1”，但这里是输出

the var  🗿rock type is: StringChoose is ok : 🗿rock and the type is: StringChoose is ok : scissors️ and the type is: String

here for some reason it returns null, HELP! null

Game 1 P2Choose is ok : 🗿rock and the type is: StringChoose is ok : scissors️ and the type is: String

here for some reason it returns null, HELP! null

Game 2 P2Choose is ok : rock and the type is: StringChoose is ok : scissors and the type is: String

here for some reason it returns null, HELP! [scissors, lizard]

But the function is working fine: P1

所以...我真的不知道发生了什么，提前致谢

我已经在

HashMap

选项中尝试使用

Map

、

MutableMap

和

whoWins()