我希望将所有与group_id匹配的行作为输入
例如
这是我的桌子:-
id | name | group_id
----+----------------+----------
1 | Alice John | {1,2,3}
2 | joshn shukla | {1,4}
3 | rishikesh jain | {2,8}
当我执行以下查询时:-
select * from employee where group_id::TEXT ~ '[\{,]2,8[,\}]'
然后返回结果成为
id | name | group_id
----+----------------+----------
3 | rishikesh jain | {2,8}
预期结果全部匹配:-
id | name | group_id
----+----------------+----------
1 | Alice John | {1,2,3}
3 | rishikesh jain | {2,8}
因为两行中都存在2。任何解决方案?
尝试:
select * from employee where (group_id @> '{2}' or group_id @> '{8}');