如何获取摩卡以使用http响应?

问题描述 投票:0回答:1

我的http调用返回一个函数,所以我的比较总是失败,因为[Function]不等于我的值。

如何获得我的断言以在其中使用true / false标志?

# test/helloWorld.js
const other_functions = require('../other_file');
describe('function from other file,visits URL', function() {
  it('should visit example.com', function() {
    result = other_functions.oo
    console.log(result);
    assert.equal(result, true);
  }); 
});
# other_file.js
const request = require('request')
var http_call = request('http://example.com', function (error, response, body) {
  console.error('error:', error);
  console.log('statusCode:', response && response.statusCode);
  console.log('body:', body);
  if(body.match(/Example Domain/)) {
    return true
  }
  else {
    return false
  }
});
exports.oo = () => {
  return http_call
}
npm test
...
AssertionError [ERR_ASSERTION]: [Function] == true       
...
javascript node.js mocha chai
1个回答
0
投票

回调不返回值,因此您需要传递回调以获取值或将其更改为使用Promise样式。像这样的东西

const request = require('request')
function http_call() {
  return new Promise((resolve, reject) => {
    request('http://example.com', function (error, response, body) {
      console.error('error:', error);
      console.log('statusCode:', response && response.statusCode);
      console.log('body:', body);
      if(body.match(/Example Domain/)) {
        resolve(true)
      }
      else {
        resolve(false);
      }
    });
  });
}

module.exports = http_call;

然后您可以在测试中进行

const http_call = require('../other_file');
describe('function from other file,visits URL', function() {
  it('should visit example.com', async function() {
    const result = await http_call();
    console.log(result);
    assert.equal(result, true);
  }); 
});

希望这会有所帮助

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