[添加带有match="/"
的模板,该模板创建想要的根元素作为文字结果元素,并且内部创建<xsl:apply-templates/>
您好,我需要使用XSLT映射来转换XML,但我不知道该怎么做……您能帮我吗?>
我的源XML:
<?xml version="1.0" encoding="UTF-8"?> <order-header> <id type="integer">1</id> <created-at type="dateTime">2020-01-25T18:59:02-03:00</created-at> <updated-at type="dateTime">2020-04-23T15:28:13-03:00</updated-at> <po-number>1</po-number> <price-hidden type="boolean">false</price-hidden> <acknowledged-flag type="boolean">false</acknowledged-flag> <acknowledged-at nil="true"/> <status>issued</status> <transmission-status>sent_via_email</transmission-status> <version type="integer">1</version> <internal-revision type="integer">3</internal-revision> <exported type="boolean">false</exported> <last-exported-at nil="true"/> <payment-method>invoice</payment-method> <ship-to-attention>10422282000179</ship-to-attention> <coupa-accelerate-status nil="true"/> <change-type>revision</change-type> <transmission-method-override>supplier_default</transmission-method-override> <transmission-emails></transmission-emails> </order-header>
我需要这个结果:
<?xml version="1.0" encoding="UTF_8"?> <ns0:MT_CRIAALTSAP_RES xmlns:ns0="urn:xxxx:xxxxxx"> <order_header> <id type="integer">1</id> <created_at type="dateTime">2020-01-25T18:59:02-03:00</created_at> <updated_at type="dateTime">2020-04-23T15:28:13-03:00</updated_at> <po_number>1</po_number> <price_hidden type="boolean">false</price_hidden> <acknowledged_flag type="boolean">false</acknowledged_flag> <acknowledged_at nil="true"/> <status>issued</status> <transmission_status>sent_via_email</transmission_status> <version type="integer">1</version> <internal_revision type="integer">3</internal_revision> <exported type="boolean">false</exported> <last_exported_at nil="true"/> <payment_method>invoice</payment_method> <ship_to_attention>10422282000179</ship_to_attention> <coupa_accelerate_status nil="true"/> <change_type>revision</change_type> <transmission_method_override>supplier_default</transmission_method_override> <transmission_emails></transmission_emails> </order_header> </ns0:MT_CRIAALTSAP_RES>
我在下面使用此代码,这是我在论坛中获取的代码:
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" version="1.0"> <xsl:output method="xml" indent="yes"/> <xsl:template match="*[contains(local-name(.), '-')]"> <xsl:element name="{translate(local-name(),'-','_')}"> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:element> </xsl:template> <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet>
代码运行正常,但我需要根元素为
<ns0:MT_CRIAALTSAP_RES xmlns:ns0="urn:xxxx:xxxxxx">
您能帮我解决这个问题吗?
先花点时间
您好,我需要使用XSLT映射来转换XML,但我不知道该怎么做……可以帮助我吗?我的源XML: [添加带有match="/"
的模板,该模板创建想要的根元素作为文字结果元素,并且内部创建<xsl:apply-templates/>
[添加带有match="/"
的模板,该模板创建想要的根元素作为文字结果元素,并且内部创建<xsl:apply-templates/>