x = input("Please enter your DNA sequence: ")
k = []
hi = [["Phenylalanine","UUU"],["Leucine","UUA"]]
z = {'A' : 'U', 'T' : 'A', 'G' : 'C', 'C' : 'G'}
for i in x:
l = z[i]
k.append(l)
k = ''.join(k)
print("Your RNA sequence is :" + k)
t = [k[i:i+3] for i in range(0, len(k), 3)]
for t in t:
a = hi[2]
b = t[1]
o = [i for i, j in zip(a, b) if i == j]
print("The Amino acid cequence is" + (o) + ".")
[我想要一个代码,如果我输入AAAAAT,它将把它更改为[UUU,UUA],然后在hi列表中找到它并显示“氨基酸序列是苯丙氨酸,亮氨酸。”我不怎么有人可以帮忙吗?
代码段存在一些突出的问题:
a = hi[2]
:hi
只有2个元素,但您正在尝试访问第三个元素for t in t
请勿使用列表变量本身遍历列表。 已经说过,解决此问题的直接方法是将hi
做成字典
hi_dict = {"UUU":"Phenylalanine","UUA":"Leucine"}
并将结果字符串保留在循环之外。
answer= "The Amino acid cequence is "
for ti in t:
answer = answer + hi_dict [ti] +" "
print(answer)
示例:
Please enter your DNA sequence: AAAAAT
Your RNA sequence is :UUUUUA
The Amino acid cequence is Phenylalanine Leucine
DAN_TO_AA = {
'ATA':'I', 'ATC':'I', 'ATT':'I', 'ATG':'M',
'ACA':'T', 'ACC':'T', 'ACG':'T', 'ACT':'T',
'AAC':'N', 'AAT':'N', 'AAA':'K', 'AAG':'K',
'AGC':'S', 'AGT':'S', 'AGA':'R', 'AGG':'R',
'CTA':'L', 'CTC':'L', 'CTG':'L', 'CTT':'L',
'CCA':'P', 'CCC':'P', 'CCG':'P', 'CCT':'P',
'CAC':'H', 'CAT':'H', 'CAA':'Q', 'CAG':'Q',
'CGA':'R', 'CGC':'R', 'CGG':'R', 'CGT':'R',
'GTA':'V', 'GTC':'V', 'GTG':'V', 'GTT':'V',
'GCA':'A', 'GCC':'A', 'GCG':'A', 'GCT':'A',
'GAC':'D', 'GAT':'D', 'GAA':'E', 'GAG':'E',
'GGA':'G', 'GGC':'G', 'GGG':'G', 'GGT':'G',
'TCA':'S', 'TCC':'S', 'TCG':'S', 'TCT':'S',
'TTC':'F', 'TTT':'F', 'TTA':'L', 'TTG':'L',
'TAC':'Y', 'TAT':'Y', 'TAA':'_', 'TAG':'_',
'TGC':'C', 'TGT':'C', 'TGA':'_', 'TGG':'W',
}
DAN_TO_RNA = {"A": "U", "T": "A", "G": "C", "C": "G"}
seq = "AAAAAT"
rna = " ".join(
[DAN_TO_RNA.get(seq[i : i + 3], seq[i : i + 3]) for i in range(0, len(seq), 3)]
)
protein = "".join([DAN_TO_AA.get(seq[i : i + 3], "-") for i in range(0, len(seq), 3)])
print(f"Your RNA sequence is {rna}")
print(f"The Amino acid cequence is {protein}")