Django Json通过id过滤了查询集

问题描述 投票:0回答:1

我的目标是获取id并使用id过滤查询集,如下面的代码所示:

views.朋友

class MyProfile(TemplateView):
model = Reports
template_name = 'template.html'
def get_context_data(request, *args, **kwargs):
    if kwargs.get('pk', None):
        q = kwargs.get('pk', None)
        queryset = Reports.objects.all().values('id','line_x','line_y',).filter(id = q)
        data = list(queryset)
        return JsonResponse(data, safe=False)

URLs.朋友

url(r'^profiles/(?P<pk>\d+)/$', views.MyProfile.as_view())

它返回以下错误:

context必须是dict而不是JsonResponse

Django 1.11.8

json django django-queryset
1个回答
1
投票
from django.http import JsonResponse

def different_function_name(request, *args, **kwargs):
    if kwargs.get('pk', None):
       q = kwargs.get('pk', None)
       queryset = Reports.objects.all().values('id','line_x','line_y',).filter(id = q) 
       query_list = list(queryset)
       return JsonResponse(query_list, safe=False)
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