用对象键中的另一个替换字符

Question

我正在学习如何使用jq操作json数据，我有一点麻烦。这是我输入的JSON

{
   "user":{
      "advertisingID":"617a68"
   },
   "deviceTs":1575387020137,
   "activies":[
       {
         "ts":1575617868326,
         "appsUsage":{
            "isFull":true,
            "data":[
               {
                  "com.orange.phone":44009
               }
            ],
            "startTs":1575617281541
         }
      },
      {
         "ts":1575618968326,
         "appsUsage":{
            "isFull":true,
            "data":[
               {
                  "uk.green.launcher2":4354
               },
               {
                  "com.black.phone":1232
               }
            ],
            "startTs":1575617281541
         }
      }
   ]
}

我想将所有包含“点”的键替换为“破折号”和预期的输出：

{
   "user":{
      "advertisingID":"617a68"
   },
   "deviceTs":1575387020137,
   "activies":[
       {
         "ts":1575617868326,
         "appsUsage":{
            "isFull":true,
            "data":[
               {
                  "com-orange-phone":44009    <----
               }
            ],
            "startTs":1575617281541
         }
      },
      {
         "ts":1575618968326,
         "appsUsage":{
            "isFull":true,
            "data":[
               {
                  "uk-green-launcher2":4354   <----
               },
               {
                  "com-black-phone":1232      <----
               }
            ],
            "startTs":1575617281541
         }
      }
   ]
}

我尝试过。activies | = map（with_entries（如果.key ==“ appsUsage”然后... else。end））...（split（“。”）| join（“-”））但没有成功，预先感谢。

Answer 1

我认为您不需要正则表达式；我相信split和join内置函数的结合将更有效和干净。

.activies |= walk(
  if type == "object" then
    reduce (keys_unsorted[] | select(index("."))) as $k (.;
      (.[$k | split(".") | join("-")] = .[$k])
      | del(.[$k])
    )
  else . end
)

^{Online demo}

根据峰的建议，一种更具可读性的解决方案：

.activies |= walk(
  if type == "object" then
    with_entries(
      .key |= gsub("\\.";"-")
    )
  else . end
)

^{Online demo}