问题是——如何从 Twig 模板中的服务中获取结果?
版本: 交响乐 6.1.12 PHP 8.1.6
我有 Navigation 类,它使用 getNavigation() 方法返回 Navigation 数组:
namespace App\Service;
use Symfony\Component\Routing\RouterInterface;
class Navigation
{
private RouterInterface $router;
private array $navigation = [];
public function __construct(RouterInterface $router)
{
$this->router = $router;
$this->setNavigation();
}
public function setNavigation(array $nav = []): void
{
$this->navigation = $nav;
if(empty($this->navigation)) {
$this->navigation = [
'Home' => $this->router->generate('homepage'),
'Products' => $this->router->generate('products'),
'Contacts' => $this->router->generate('contacts'),
];
}
}
public function getNavigation(): Array
{
return $this->navigation;
}
}
现在它通过调用每个控制器中的类来工作(例如:)
public function __construct(Navigation $navigation)
{
$this->navigation = $navigation;
}
// #[Route('/', name: 'homepage')]
public function index(): Response
{
return $this->render('home/index.html.twig', [
'navigation' => $this->navigation->getNavigation(),
]);
}
是否有可能在
nav.html.twig template
中访问该服务而无需每次都调用该实例?
我尝试通过
将服务保存在services.yaml中services:
app.navigation:
class: App\Service\Navigation
然后在树枝中通过
{{ app.navigation.getNavigation() }}
获取访问权限,但它不起作用。
提前感谢您的回答。
有2种方法。
config/packages/twig.yaml twig: #... globals: #the value is the service's id navigation: '@App\\Service\\Navigation' // maybe service id app.navigation
在树枝中使用它:
{{navigation.getNavigation()}}
我认为你应该改变服务定义方法。看看Symfony服务
在我看来最好的方法是写一个树枝扩展并调用服务类
https://symfony.com/doc/current/templates.html#writing-a-twig-extension
// App/Twig/NavigationExtension.php
namespace App\Twig;
use App\Service\Navigation;
use Twig\Extension\AbstractExtension;
use Twig\TwigFunction;
class NavigationExtension extends AbstractExtension
{
private $navigation;
public function __construct(Navigation $navigation)
{
$this->navigation = $navigation;
}
public function getFilters(): array
{
return [];
}
public function getFunctions(): array
{
return [
new TwigFunction('getNavigation', [$this, 'getNavigation']),
];
}
public function getNavigation()
{
return $this->navigation->getNavigation();
}
}