打字稿无法识别对象中的箭头函数类型

Question

我目前正在研究一种类型安全的方法来声明一个接口，该接口声明一个函数应该如何返回一个对象。该对象应始终包含相同的功能。接口声明如下：

import { DrawingMode } from '@/Pages/Planning/PlanningTypes'
import { Ref } from 'vue'

interface toggleable {
    reenable: () => void
    disable: () => void
}

interface createableByDraw {
    startDrawing: (drawingMode: DrawingMode) => void
    onCreated: (layer: L.Layer, drawingMode: DrawingMode) => void
}

export interface LeafletConnectionHookReturnObject
    extends toggleable,
        createableByDraw {}

export type LeafletConnectionHook = (
    currentMap: Ref<L.Map | undefined>
) => LeafletConnectionHookReturnObject

函数是这样实现的：

export const useMappedXY: LeafletConnectionHook = (
    currentMap: Ref<L.Map | undefined>
) => {
    const onCreated = (layer: L.Layer) => {

    }


    const startDrawing = () => {
    }


    const reenable = (anyStringThatShouldNotBeAllowed: string) => {

    }

    const disable = () => {
    }

    return {
        reenable,
        disable,
        startDrawing,
        onCreated,
    }
}

如您所见，“onCreated”和“startDrawing”都没有正确实现接口。 “重新启用”功能甚至需要一个与界面建议的参数完全不同的参数。 当我在任何其他地方使用我的 useMappedXY 函数时，typescript 期望 reenable 函数正确实现接口。为什么会这样，我该怎么做才能正确执行接口？

如果我这样重写我的函数：

export const useMappedXY: LeafletConnectionHook = (
    currentMap: Ref<L.Map | undefined>
) => {
    const onCreated = (layer: L.Layer) => {

    }


    const startDrawing = () => {
    }


    const reenable = (anyStringThatShouldNotBeAllowed: string) => {

    }

    const disable = () => {
    }

    const returnObject = {
        reenable,
        disable,
        startDrawing,
        onCreated,
    }

    return returnObject
}

然后打字稿确实正确地推断出 returnObject 没有正确实现接口。但这对我来说似乎很容易被利用并且容易出错