创建一个读取文件的函数，存储在数组中，然后打印单词在数组中出现的次数

Question

我想创建一个函数；

• 读取文本文件，逐字读取文件，并将这些字存储在数组中。

• 计算每个单词的出现次数，并且每个单词在数组中仅存储一次。

• 输出每个单词，并在其旁边显示其出现次数。

示例：

文本文件说：“弗兰克吃豌豆吃薯条豌豆”

将创建一个数组，[坦率，吃，豌豆，吃，薯条，豌豆]

然后，将打印最终产品；

坦率1吃2豌豆2薯条1

-

这是我到目前为止所拥有的

def countWordsInFile():
    array = []
    array2 = [1,2,3,4,5]
    length = len(array)
    fileName = getUserText("Enter the name of the file you want to read array from")
    openFile = openNewFile(fileName,"read")
    i = openFile
    for words in i.read().split():
        array.append(words)
    print(array)

    for i in range(0,length,1):
        count = array.count[i]
        array2.append(count)
    print(array2)

Answer 1

您可以为此使用字典，更改后的代码如下：

def countWordsInFile():
    array = []
    array2 = [1,2,3,4,5]
    length = len(array)
    fileName = getUserText("Enter the name of the file you want to read array from")
    openFile = openNewFile(fileName,"read")
    i = openFile
    for words in i.read().split():
        array.append(words)
    print(array)

    words = {}
    for word in array:
        if word not in words:
            words[word] = 1
        else:
            words[word] += 1
    print(words)