quarkus中如何处理超时异常？

Question

我正在尝试从 quarkus 控制器连接到第三方 API。我有一个使用服务方法的控制器。 try catch 块不起作用。我拥有所有必需的依赖项，并且遵循 quarkus 文档 这是代码

控制器

package com.ncr.invoice;

// all imports over here 

@Path("/api")
@RequestScoped
public class InvoiceController {
    // all variable and injection 
    @POST
    @Consumes(MediaType.APPLICATION_JSON)
    @Produces(MediaType.APPLICATION_JSON)
    @Path("/invoice")
    @Timeout(250)
    @PermitAll
    public Response getInvoice(AuthTokenRequestModel atrm){
            SoupResponseInvoiceDetail srid = null;
            try{
                 srid = service.getInvoice(
                    atrm.getMcn(),"transactionId", atrm.getInvoiceNumber()
                 );
                 LOG.info("try block end");
            }
            catch(InterruptedException e)
            {
                LOG.info("Over here");
                return Response.status(401).build();
            }
          
            return Response.ok(srid).build();
        }

        return Response.status(401).build();
    }

 
    // all getter setter 
}

服务

package com.ncr.invoice;

//all imports 

@Path("/")
@RegisterRestClient(configKey="invoice-api")
@ClientHeaderParam(name = "Authorization", value = "{basicAuth}")
public interface InvoiceService {

    @GET
    @Produces(MediaType.APPLICATION_JSON)
    @Path("/")
    public SoupResponseInvoiceDetail getInvoice(@QueryParam("id") String id,@QueryParam("txn_id") String txnId, @QueryParam("invoice") String invoice) throws InterruptedException;

    default String basicAuth() {
        String uName = ConfigProvider.getConfig().getValue("auth.username", String.class);
        String pwd = ConfigProvider.getConfig().getValue("auth.pwd", String.class);
        String creds =  uName + ":" + pwd;
        return "Basic " + Base64.getEncoder().encodeToString(creds.getBytes());
    }
}

我遇到的错误 2021-01-07 13:07:42,286 INFO [com.ncr.inv.InvoiceController] (executor-thread-189) 尝试块结束 2021-01-07 13:07:42,555 错误 [io.und.req.io] (executor-thread-189) 异常处理请求 58a6d4b3-76c1-4a8b-b4a0-1e241219fb4d-4 到 /api/invoice: org.jboss .resteasy.spi.UnhandledException：org.eclipse.microprofile.faulttolerance.exceptions.TimeoutException：超时[com.ncr.invoice.InvoiceController#getInvoice]超时 在 org.jboss.resteasy.core.ExceptionHandler.handleApplicationException(ExceptionHandler.java:106) 在 org.jboss.resteasy.core.ExceptionHandler.handleException(ExceptionHandler.java:372) 在 org.jboss.resteasy.core.SynchronousDispatcher.writeException(SynchronousDispatcher.java:218) 在 org.jboss.resteasy.core.SynchronousDispatcher.invoke（SynchronousDispatcher.java:519） 在 org.jboss.resteasy.core.SynchronousDispatcher.lambda$invoke$4(SynchronousDispatcher.java:261) 在 org.jboss.resteasy.core.SynchronousDispatcher.lambda$preprocess$0(SynchronousDispatcher.java:161) ................................................

Answer 1

对我来说，你需要做这样的事情：

@Provider
public class TimeoutExceptionMapper implements ExceptionMapper<TimeoutException> {
    private static final Logger LOGGER = LoggerFactory.getLogger(java.lang.invoke.MethodHandles.lookup().lookupClass());    
    @Override
    public Response toResponse(TimeoutException exception) {
        LOGGER.warn(exception.getMessage());
        return getResponse();
    }

    public static Response getResponse() {      
        ErrorResponse response = new ErrorResponse();
        response.setDescription("Operation timet out, try again later");
        return status(Response.Status.GATEWAY_TIMEOUT).entity(response).build();
    }
}