这可能是一个简单答案的问题,但我尝试了谷歌搜索结果提供的每个解决方案,但无法在VS 2017中解决这个问题。我有一个带有私有析构函数的结构B
。我有另一个结构A
,它是struct B
的朋友,并试图迭代结构B
的唯一指针向量。但我一直收到这个错误:
严重级代码描述项目文件行抑制状态错误C2248'ProjectNamespace :: NwSpec :: ~NwSpec':无法访问类'ProjectNamespace :: NwSpec'中声明的私有成员'TestProject c:\ program files(x86)\ microsoft visual studio \ 2017 \ community \ _vc \ tools \ msvc \ 14.14.26428 \ include \ memory 2055
任何指针将不胜感激。谢谢。
struct A
{
//functions
std::vector<std::unique_ptr<NwSpec>> List;
bool function()const;
};
struct NwSpec
{
char* Path;//Assume Path is initialized and set with a string.
private:
~NwSpec();
friend struct A;
};
bool A::function()const
{
for (uint32_t i = 0 ; i < List.size(); i++)
{
OutputDebugStringA(List[i]->Path);// Error C2248
}
// I used iterator to the vector, but getting same error.
// I used for(const auto& k : List) but getting same access error.
// NwSpec is visible to A and within ProjectNamespace
}
您需要创建一个负责删除NwSpec对象的专用类型,并将其提供给std::unique_ptr
:
struct NwSpec;
struct A {
private:
struct NwSpecDeleter {
//Note that we're only declaring the function, and not defining it
void operator()(NwSpec * ptr) const;
};
public:
typedef std::unique_ptr<NwSpec, NwSpecDeleter> ptr_type;
std::vector<ptr_type> List;
bool function()const;
};
struct NwSpec {
char* Path;//Assume Path is initialized and set with a string.
private:
~NwSpec();
friend struct A;
};
NwSpec::~NwSpec() {}
void A::NwSpecDeleter::operator()(NwSpec * ptr) const {
delete ptr;
}
int main() {
A a;
a.List.emplace_back(new NwSpec());
auto ptr = a.List.back().release();
//This will not compile, as intended
//delete ptr;
//Nor will this:
//ptr->~NwSpec();
//But this will compile, because the original unique_ptr is perfectly capable of deleting objects:
a.List.back().reset(ptr);
a.List.back().reset();//Object is successfully deleted
a.List.erase(a.List.begin(), a.List.end());
a.List.emplace_back(new NwSpec());
//This also compiles
a.List.erase(a.List.begin(), a.List.end());
return 0;
}
这段代码可以是tested here。