SQL：如何在列中查找不同的值？

Question

我有以下 Oracle SQL 表，其中

product_id

101 和 103 分别在

attr1

和

attr3

列中具有不同的值。

data

| PRODUCT_ID | ATTR1 | ATTR2 | ATTR3 |
|------------|-------|-------|-------|
| 101        | a     | x     | z     |
| 101        | a     | x     | z     |
| 101        | aa    | x     | z     |
| 102        | b     | y     | z     |
| 102        | b     | y     | z     |
| 103        | c     | z     | z     |
| 103        | c     | z     | zz    |

如果有 7000 行和 30 列要检查此逻辑，获得突出显示差异的输出查询的最有效方法是什么？

output

| PRODUCT_ID | DESCR            |
|------------|------------------|
| 101        | Issue with attr1 |
| 103        | Issue with attr3 |

query

WITH data AS (
   
   SELECT 101 product_id, 'a' attr1, 'x' attr2, 'z' attr3 FROM dual
   UNION ALL
   SELECT 101 product_id, 'a' attr, 'x' attr2, 'z' attr3  FROM dual
   UNION ALL
   SELECT 101 product_id, 'aa' attr, 'x' attr2, 'z' attr3  FROM dual
   UNION ALL
   SELECT 102 product_id, 'b' attr, 'y' attr2, 'z' attr3  FROM dual
   UNION ALL
   SELECT 102 product_id, 'b' attr, 'y' attr2, 'z' attr3  FROM dual
   UNION ALL
   SELECT 103 product_id, 'c' attr, 'z' attr2, 'z' attr3  FROM dual
   UNION ALL
   SELECT 103 product_id, 'c' attr, 'z' attr2, 'zz' attr3  FROM dual
   
)

SELECT product_id, 'Issue with attr1' descr FROM data GROUP BY product_id HAVING COUNT(DISTINCT attr1) > 1
UNION
SELECT product_id, 'Issue with attr2' descr FROM data GROUP BY product_id HAVING COUNT(DISTINCT attr2) > 1
UNION
SELECT product_id, 'Issue with attr3' descr FROM data GROUP BY product_id HAVING COUNT(DISTINCT attr3) > 1
;