如何替换列中的空白？熊猫

Question

我尝试了什么？

//1    myDataFrame['Gender'] = myDataFrame['Gender'].replace('^\s*$', np.nan)
//2    myDataFrame['Gender'] = myDataFrame['Gender'].replace('', np.nan)
       myDataFrame.to_csv('new_Paymets_Loan.csv')

空白仍然是csv文件。

[！[在此处输入图片描述] [1]] [1]

Gender
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Female
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Answer 1

它的工作得到纠正，因为如果默认情况下将丢失的值写入文件是空字符串，则它是参数na_rep=''。

因此有必要进行更改，也要使用Series.str.replace进行替换，然后将Series.str.replace添加到na_rep：

DataFrame.to_csv

Answer 2

您可以使用以下命令删除空格

DataFrame.to_csv

您可以使用apply方法应用于所有行

Answer 3

我认为您需要

myDataFrame['Gender'] = myDataFrame['Gender'].str.replace('^\s*$', np.nan)
myDataFrame.to_csv('new_Paymets_Loan.csv', na_rep = 'NaN')

和myDataFrame['Gender'] = re.sub('\s','',myDataFrame['Gender']) ，然后可以使用Series.replace和Series.replace保存它（默认为regex=True）

DataFrame.to_csv

Answer 4

您要在text csv文件中使用string DataFrame.to_csv。只需将其放在DataFrame中即可：

na_rep='NaN'