如何动态地添加多个的TextView到定义的LinearLayout main.xml中

问题描述 投票:8回答:2

我知道这是可能的一些布局,像ButtonTextView添加到LinearLayout。我想基于for循环的条件,创造更多然后一个TextView

我有我自己的方式尝试过,但我不能来创建它。有谁知道如何创建呢?

for循环将根据情况有所不同。请帮我对此。是否有可能创造TextView的阵列?

我已经设置与布局

setContentView(R.layout.result_page);

我使用的功能到该视图添加到现有的观点:

该功能是:

public void addAll()
{
     LinearLayout layout = (LinearLayout)findViewById(R.id.myLayout);     
     layout.setOrientation(1);       
     TextView name[] = null;     
     TextView website[] = null;     
     TextView category[] = null;        
     for (int i = 0; i < 5; i++) 
     {         
         name[i] = new TextView(this);         
         name[i].setText("Name = Shreyash");         
         website[i] = new TextView(this);         
         website[i].setText("Website = shreyah.co.cc");         
         category[i] = new TextView(this);         
         category[i].setText("Website Category = OWN");         
         layout.addView(name[i]);         
         layout.addView(website[i]);         
         layout.addView(category[i]);     
    } 
}

但在那之后,如果我运行应用程序,它显示了我的错误,如:

09-08 11:03:28.755: ERROR/AndroidRuntime(318): FATAL EXCEPTION: main
09-08 11:03:28.755: ERROR/AndroidRuntime(318): java.lang.RuntimeException: Unable to start activity ComponentInfo{com.quiz.spellingquiz/com.quiz.spellingquiz.ResultDisplayPage}: java.lang.NullPointerException
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2663)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2679)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.ActivityThread.access$2300(ActivityThread.java:125)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.ActivityThread$H.handleMessage(ActivityThread.java:2033)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.os.Handler.dispatchMessage(Handler.java:99)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.os.Looper.loop(Looper.java:123)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.ActivityThread.main(ActivityThread.java:4627)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at java.lang.reflect.Method.invokeNative(Native Method)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at java.lang.reflect.Method.invoke(Method.java:521)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:868)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:626)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at dalvik.system.NativeStart.main(Native Method)
09-08 11:03:28.755: ERROR/AndroidRuntime(318): Caused by: java.lang.NullPointerException
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at com.quiz.spellingquiz.ResultDisplayPage.addAll(ResultDisplayPage.java:59)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at com.quiz.spellingquiz.ResultDisplayPage.onCreate(ResultDisplayPage.java:34)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1047)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2627)
09-08 11:03:28.755: ERROR/AndroidRuntime(318):     ... 11 more

我在哪里错对此?

我买了DeeV的代码是这样的结果:

但我想设置的标签词下的Word和标签回答下答案。但它是如何可能的?我觉得我有另设的LinearLayout了点。我如何设置其他的LinearLayout该类型的外观?

android android-layout android-emulator android-widget android-ndk
2个回答
12
投票

你只需要如果以后需要改变TextViews创建一个数组。然而,如果你确实需要进行一个数组,那么这样的事情应该工作。

List<TextView> textList = new ArrayList<TextView>(NUM_OF_TEXTS);
for(int i = 0; i < NUM_OF_TEXTS; i++)
{
   TextView newTV = new TextView(context);
   newTV.setText("New message.");
   newTV.setTextColor(0xFFFF0000);
   /**** Any other text view setup code ****/
   myLinearLayout.addView(newTV);
   textList.add(newTV);
}

如果静态一旦创建文本,那么你可以简单地删除在代码列表中的任何引用,它仍然会被添加到LinearLayout

编辑:

假设我理解你的问题吧,你想要的布局是这样的:

Word:
Big
Answer:
42

Word:
Small
Answer:
Tough

Word:
Example
Answer:
Another Answer

在这种情况下,你从字面上没有做太多。 LinearLayout会把一切都在你addView放置的顺序。更新我以前的代码,这应该工作:

List<TextView> wordList = new ArrayList<TextView>(NUM_OF_WORDS);
List<TextView> answerList = new ArrayList<TextView>(NUM_OF_ANSWERS);

for(int i = 0; i < NUM_OF_WORDS; i++){
   TextView blankText = new TextView(context);
   TextView wordText = new TextView(context);
   TextView answerText = new TextView(context);
   blankText.setText(" ");
   wordText.setText("Word:");
   answerText.setText("Answer:");

   TextView newWord = new TextView(context);
   newWord.setText(**** some method of getting the word ****);
   TextView newAnswer = new TextView(context);
   newAnswer.setText(**** some method of getting the answer ****);
   /**** Any other text view setup code ****/

   myLinearLayout.addView(wordText);
   myLinearLayout.addView(newWord);
   myLinearLayout.addView(answerText);
   myLinearLayout.addView(newAnswer);
   myLinearLayout.addView(blankText);

   wordList.add(newWord);
   answerList.add(newAnswer);
}

2
投票
        LinearLayout lila = new LinearLayout(this);
        ArrayList<Button> alb = new ArrayList<Button>();
        int nButton = 10;
        for (int i = 0; i < nButton; i++)
        {
            alb.add(new Button(this));
            lila.addView(alb.get(i));
        }
        //works the same way with TextView
        alb.get(5).setText("myButton");

也许这可以帮助。

编辑:对不起严格一样DeeV。

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