分割字符串与蟒蛇正则表达式分隔符

Question

我有以下字符串：

txt='agadsfa_(2asdf_sdfsaf)asfsadf[adsf_klnalfk;jn234kmafs)adfs,nlnawr23'

这是分隔符：

delimiters = " \t,;.?!-:@[](){}_*/"

作为输出，我想此值列表：

"agadsfa","2asdf","sdfsaf","asfsadf","adsf","klnalfk","jn234kmafs","adfs","nlnawr23"

我尝试使用正则表达式：

re.split(delimiters,txt)

但我发现了这个错误：

re.error: unterminated character set at position 10

这里有什么问题？

Answer 1

正则表达式是不正确。而从评论，您已经添加了delimiters字符串不被感动的需求。

我们需要做的是什么，是处理输入字符串，并将其转换成可以通过split()使用适当的正则表达式。这是如何做：

# need to enclose regex in [], we want to split on any of
# the chars; also some of the chars need to be escaped    
delimiters = ' \t,;.?!-:@[](){}_*/'
regex = delimiters.replace(']', '\]').replace('-', '\-')
regex = r'[{}]+'.format(regex)

如预期的结果：

txt = 'agadsfa_(2asdf_sdfsaf)asfsadf[adsf_klnalfk;jn234kmafs)adfs,nlnawr23'
re.split(regex, txt)
=> ['agadsfa', '2asdf', 'sdfsaf', 'asfsadf', 'adsf', 'klnalfk', 'jn234kmafs', 'adfs', 'nlnawr23']

Answer 2

Python 3的代码

import re

txt="agadsfa_(2asdf_sdfsaf)asfsadf[adsf_klnalfk;jn234kmafs)adfs,nlnawr23"

delimiters = "_|;|,|\)|\(|\[|\]"

list(filter(None, re.split(delimiters, txt)))

产量

['agadsfa', '2asdf', 'sdfsaf', 'asfsadf', 'adsf', 'klnalfk', 'jn234kmafs', 'adfs', 'nlnawr23']

由单独的符号|并使用蟒蛇名单过滤功能，避免空字符串

Answer 3

你必须使用|分裂您的分隔符：

delimiters = r' |\t|,|;|\.|\?|!|-|:|@|\[|\]|\(|\)|\{|\}|_|\*|/'
# then use this to eliminate empty strings if you have two delimiters next to each other
print([w for w in re.split(delimiters,txt) if w])   
# or list(filter(lambda a: a, re.split(delimiters,txt)))

结果是：

['agadsfa', '2asdf', 'sdfsaf', 'asfsadf', 'adsf', 'klnalfk', 'jn234kmafs', 'adfs', 'nlnawr23']

Answer 4

尝试这个：

import re

txt = "agadsfa_(2asdf_sdfsaf)asfs?adf[adsf_klna!lfk;jn234kmafs)adfs, nlnawr*23"

line = re.sub(
           r"[ \t,;\.?!\-:@\[\](){}_*/]+", 
           r",", 
           txt
       )

print(line.split(","))