我试图让用户输入三个输入:用户名,ID和备用ID。如果用户输入用户名的回车,则程序应结束。如果用户输入用户名并输入后两个ID的返回值,则输入应显示为无效。我试过使用cin,fgets和get(我知道get通常是不好的编程)。使用cin时,我尝试使用cin.clear()和cin.ignore()跳过换行符。第一个输入始终有效,但是第二个输入调用不断被跳过。
代码段:
int main(){
string name, altID, tempUWFID;
char input;
cout << "Name> ";
// if (cin.get() == '\n') - This was one way that I tried.
if ((input = getchar()) == '\n')
break;
else
cin >> name;
cout << "UWF ID> ";
if ((input = getchar()) != '\n')
cin >> tempUWFID;
cout << "Alternate ID> ";
if ((input = getchar()) != '\n')
cin >>altID;
cout << "\nThank you for abusing my program, have a nice day!\n";
输出:
Welcome to Voter's Registration
Name> johnny
UWF ID> Alternate ID>
ad
Invalid UWF ID
Name>
Thank you for abusing my program, have a nice day!
预期输出:
Welcome to Voter's Registration
Name> johnny
UWF ID> somenumber
Alternate ID> someothernumber
Invalid UWF ID
Name>
Thank you for abusing my program, have a nice day!