LP / MILP(CPLEX)困难

问题描述 投票:0回答:1

我正在尝试使用CPLEX解决优化问题。

//Variables 

int n = ...;
range time =1..n; //n definido em data

dvar float+ c[time] in 0..0.9;
dvar float+ d[time] in 0..0.9;
dvar float+ x[time];

int beta[time]=...;
float pc[time]=...;
float pd[time]=...;

//Expressions

dexpr float objective = sum(t in time) (d[t]*pd[t]-c[t]*pc[t]); 

//Model

maximize objective;

subject to {

    x[1] == 0.5;
    c[1] == 0;
    d[1] == 0;

    forall(t in time)
        const1:
            x[t] <= 1;          

    forall(t in time: t!=1)
        const2:
            (x[t] == x[t-1] + c[t] - beta[t]*d[t]);             
 }

谁能告诉我如何防止d [t]和c [t]同时大于0?

基本上我想写这个:

if( d[t] > 0) c[t] = 0; 

谢谢,

linear-programming cplex nonlinear-optimization mixed-integer-programming
1个回答
0
投票

您可以使用逻辑约束:

( d[t] <= 0) || (c[t] <= 0);
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