id

问题描述 投票:0回答:1

我有两张表,如下所示

NA_table
+----+-------+-------+---------------+---------------------+-----+
| id | nname  | phone |      nip       |        ntime      | iid |
+----+-------+-------+---------------+---------------------+-----+
|  1 | john  | +xxxx |  192.168.1.10 | 2020-04-21 11:10:10 |  23 |
|  2 | bill  | +xxxx |  192.168.1.11 | 2020-04-21 12:10:10 |  44 |
|  3 | husky | +xxxx |  192.168.1.12 | 2020-04-21 13:10:10 |  44 |
|  4 | lab   | +xxxx |  192.168.1.13 | 2020-04-21 14:10:10 |  33 |
|  5 | bill  | +xxxx |  192.168.1.12 | 2020-04-21 11:10:15 |  44 |
|  6 | cal   | +xxxx |  192.168.1.13 | 2020-04-21 16:10:10 |  12 |
|  7 | jess  | +xxxx |  192.168.1.11 | 2020-04-21 17:10:10 |  90 |
|  8 | minn  | +xxxx |  192.168.1.12 | 2020-04-21 18:10:10 |  44 |
|  9 | jess  | +xxxx |  192.168.1.11 | 2020-04-21 17:10:10 |  21 |
+----+-------+-------+---------------+---------------------+-----+


CD_table
+----+--------------+---------------------+-------+
| cid |     cip      |       ctime        | other |
+----+--------------+---------------------+-------+
|  1 | 192.168.1.11 | 2020-04-21 03:22:19 | text  |
|  2 | 192.168.1.12 | 2020-04-21 03:10:10 | text  |
|  3 | 192.168.1.11 | 2020-04-21 06:11:12 | text  |
|  4 | 192.168.1.19 | 2020-04-21 06:10:03 | text  |
|  5 | 192.168.1.22 | 2020-04-21 13:10:10 | text  |
|  6 | 192.168.1.11 | 2020-04-21 14:14:17 | text  |
|  7 | 192.168.1.12 | 2020-04-21 16:09:10 | text  |
|  8 | 192.168.1.11 | 2020-04-22 09:07:11 | text  |
+----+--------------+---------------------+-------+

使用这两张表,我想运行以下查询

SELECT
CD_table.ctime AS CTIME,
CD_table.cip AS CIP,
CD_table.other AS OTHER,
NA_table.phone AS PHONE,
FROM NA_table
LEFT JOIN CD_table 
ON NA_table.nip = CD_table.cip 
WHERE
NA_table.NAIID = '44'
AND
NA_table.ntime between '2020-04-21 11:10:00' AND '2020-04-21 11:10:59'
AND
CD_table.ctime between '2020-04-21 00:10:00' AND '2020-04-21 23:59:59'

这给了我这个结果。

+----------------------+---------------+-------+-------+
|        CTIME         |      CIP      | OTHER | PHONE |
+----------------------+---------------+-------+-------+
| 2020-04-21 03:22:19  |  192.168.1.11 | text  | +xxxx |
| 2020-04-21 03:10:10  |  192.168.1.12 | text  | +xxxx |
| 2020-04-21 06:11:12  |  192.168.1.11 | text  | +xxxx |
| 2020-04-21 14:14:17  | 192.168.1.11  | text  | +xxxx |
| 2020-04-21 16:09:10  |  192.168.1.12 | text  | +xxxx |
+----------------------+---------------+-------+-------+

但是我希望我的输出按CTIME排序,并且只打印每个CD_table记录中最后匹配的记录,就像这样。

+---------------------+---------------+-------+-------+
|        CTIME        |      CIP      | OTHER | phone |
+---------------------+---------------+-------+-------+
| 2020-04-21 14:14:17 | 192.168.1.11  | text  | +xxxx |
| 2020-04-21 16:09:10 |  192.168.1.12 | text  | +xxxx |
+---------------------+---------------+-------+-------+

我可以在我的查询中做DESC和LIMIT部分。或者有其他的方法,我可以分割我的查询。

mysql sql left-join inner-join
1个回答
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