http帖子facebook图api处理

Question

我想通过处理applet在facebook用户的墙上发布一些东西。首先，我通过Oauth身份验证为app_id和user_id的用户获取access_token。我用这个code，谢谢Jorge

现在我想在用户的墙上发布帖子。我使用这些参数“access_token”，“XXX;”消息“，”检查......处理！“向https://graph.facebook.com/USER_ID/feed发送http发布请求！”

请求的响应是

executing request: POST https://graph.facebook.com/USER_ID/feed HTTP/1.1
----------------------------------------
HTTP/1.1 403 Forbidden
----------------------------------------
{"error":{"type":"OAuthException","message":"(#200) This API call requires a valid app_id."}}

那是什么意思？我输入了一个有效的app_id ...否则我没有得到access_token？

亲爱的，彼得

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;

void setup()
{
  String url = "https://graph.facebook.com/USER_ID/feed";

  try
  {
    DefaultHttpClient httpClient = new DefaultHttpClient();

    HttpPost          httpPost   = new HttpPost( url );
    HttpParams        postParams = new BasicHttpParams();
                      postParams.setParameter( "access_token", "XXX" );
                      postParams.setParameter( "message", "Check ... Processing!" );
                      httpPost.setParams( postParams );    

    println( "executing request: " + httpPost.getRequestLine() );

    HttpResponse response = httpClient.execute( httpPost );
    HttpEntity   entity   = response.getEntity();


    println("----------------------------------------");
    println( response.getStatusLine() );
    println("----------------------------------------");

    if( entity != null ) entity.writeTo( System.out );
    if( entity != null ) entity.consumeContent();


    // When HttpClient instance is no longer needed, 
    // shut down the connection manager to ensure
    // immediate deallocation of all system resources
    httpClient.getConnectionManager().shutdown();       

  } catch( Exception e ) { e.printStackTrace(); }

  exit();
}

Answer 1

您需要在请求的网址中包含用户ID，而不是字面上的“USER_ID”。

所以你可以这样做：

String url = "https://graph.facebook.com/"+user_id+"/feed";

或者，使用快捷方式，字面意思：

String url = "https://graph.facebook.com/me/feed";

Facebook在访问令牌中查看用户ID而不是“我”