使用c ++构建并生成带有循环的一副纸牌[重复]

Question

此问题已经在这里有了答案：

C++ - using enums to generate a deck of cards（1个答案）

[<10天前关闭。

在c ++中]

这个主意是进行设置，以便它将不断循环遍历所有卡，以得到不同的结果和答案，直到所有52张卡都消失了，我不知道确切的定位器，我知道它的位置

for(int i = 0; i < 5; i++) 
   {
     cout << i << endl;
   }

我不是很确定如何设置数组，如果我只是像字符串{ace，one two}依此类推。等等。但是我将数组标记为52，甚至将它们全部键入，只重复了13个数字4穿着4套衣服，所以您会分别将它们分类吗？还是有什么用呢？

#include <iostream>
using namespace std;
class cardGame;

int main()
{
    int bet;
    int dealer[52] = { 13, 13, 13, 13 };
    int player[52] = { 13, 13, 13, 13 };
    int dealerCard1;
    int dealerCard2;
    int playerCard1;
    int playerCard2;
    int dealerTotal;
    int playerTotal;
    int shuffle;

    cout << "This is My attempt at BlackJack" << endl;
    cout << endl;
    cin >> bet;
    cout << "Player enter amount to bet: $ ";
    cout << endl;
    cin >> shuffle;

    cardGame::playeer(playerCard1 + playerCard2 = playerTotal);
    cardsGame.playerCard1 = 0;
    cardsGame.playerCard2 = 0;
    cardsGame.playerTotal = 0;


    cout << "the First card is: " << cardsGame.playerCard1 = 0 << endl;
    cout << "The second card is: " << cardsGame.playerCard = 0 << endl;
    cout << "Your total is: " << cardsGame.playerTotal = 0 << endl;
    cardGame::playeer(playerCard1 + playerCard2 = playerTotal);

    if (playerCard1 + playerCard2 == 21)
    {
        cout << "WINNER WINNER CHICKEN DINNER!" << endl;
    };
    else (playerCard1 + playerCard2 > 21)
    {
        cout << "What a dissapointment you are to everyone!" << endl;
    };
    if (playerCard1 + playerCard2 > dealerTotal)
    {
        cout << "WINNER WINNER CHICKEN DINNER!" << endl;
    };
    else (playerCard1 + playerCard2 == dealerTotal)
    {
        cout << "What a dissapointment you are to everyone!"
    }


    cardGame::dealer(dealerCard1 + dealerCard2 = dealerTotal);
    cardsGame.dealerCard1 = 0;
    cardsGame.dealerCard2 = 0;
    cardsGame.dealerTotal = 0;



    cout << "the First card is: " << cardsGame.dealerCard1 = 0 << endl;
    cout << "The second card is: " << cardsGame.dealerCard2 = 0 << endl;
    cout << "Your total is: " << cardsGame.dealerTotal = 0 << endl;
    cardGame::dealer(dealerCard1 + playerCard2 = playerTotal);

    if (dealerCard1 + dealerCard2 == 21)
    {
        cout << "What a dissapointment you are to everyone!" << endl;
    };
    else (dealerCard1 + dealerCard2 > 21)
    {
        cout << "WINNER WINNER CHICKEN DINNER" << endl;
    }
    if (dealerCard1 + dealerCard2 > playerTotal)
    {
        cout << "What a dissapointment you are to everyone!" << cout endl:
    };
    else (dealerCard1 + dealerCard2 < playerTotal)
    {
        cout << "What a dissapointment you are to everyone!"
    }


}

它是用c ++编写的，其想法是进行设置，以便它将不断循环遍历所有卡，以保持获得不同的结果和答案，直到所有52张卡都消失了，我不知道确切的位置...

Answer 1

我不知道c ++（或二十一点）；但是下面是

in Javascript